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2 years ago

Please help me with this.

Mathematics

1 answer:

Rama09 [41]2 years ago

4 0

The image of the point (1, 2, 3) is (3, 7)

<h3>How to determine the image?</h3>

The given parameters are:

Point = (1, 2, 3)
Transformation rule = (3x, 2y + z)

In (1, 2, 3), we have:

x = 1; y = 2 and z = 3

When the rule is applied, we have:

Image = (3x, 2y + z)

Image = (3 * 1, 2 *2 + 3)

Evaluate

Image = (3, 7)

Hence, the image of the point (1, 2, 3) is (3, 7)

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Natalija [7]

Answer:

Domain and Range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively

Step-by-step explanation:

We have the functions, f(x) = eˣ and g(x) = x+6

So, their composition will be g(f(x)).

Then, g(f(x)) = g(eˣ) = eˣ+6

Thus, g(f(x)) = eˣ+6.

Since the domain and range of f(x) = eˣ are all real numbers and positive real numbers respectively.

Moreover, the function g(f(x)) = eˣ+6 is the function f(x) translated up by 6 units.

Hence, the domain and range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively.

6 0

3 years ago

Read 2 more answers

Quadrilateral TRPK ~ Quadrilateral EWMN Which statements are correct? Select all that apply. Question 8 options:

8090 [49]

For starters, we know that the angle measures have to be similar or the same, since similar shapes always contain the same angle measures. We can use the way that the letters of each shape line up to identify which angle correspond to each other. Angle R should be congruent to angle W, but angle P is not congruent to N, it would be congruent to M though. Now we get to the tricky part, figuring out line segment lengths. Again using the letters in each shape, we can see that TK and NM do not correspond to each other, and thus cannot be congruent or similar. But, with RP/WM, this is correctly lined up with each other. TR/EW, same with this one, and TK/EN is also the same. With this Info, we can figure out the dilation of the smaller shape, or just figure out if they are similar or not. (So pick B. And D.)

8 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

Yuri [45]

Let the curve C be the intersection of the cylinder

$16x^2+y^2=16$

and the plane

$x+y+z=1$

The projection of C on to the x-y plane is the ellipse

$16x^2+y^2=16$

To see clearly that this is an ellipse, le us divide through by 16, to get

$\frac{x^2}{1}+ \frac{y^2}{16}=1$

$\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1$ ,

We can write the following parametric equations,

$x=cos(t), y=4sin(t)$

for

$0\le t \le 2\pi$

Since C lies on the plane,

$x+y+z=1$

it must satisfy its equation.

Let us make z the subject first,

$z=1-x-y$

This implies that,

$z=1-sin(t)-4cos(t)$

We can now write the vector equation of C, to obtain,

$r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))$

The length of the curve of the intersection of the cylinder and the plane is now given by,

$\int\limits^{2\pi}_0 {|r'(t)|} \, dt$

But

$r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))$

$|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}$

$\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184$

Therefore the length of the curve of the intersection intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0

3 years ago

Explain how bias in the survey might have affected the results. A survey asks teens, “Do you, like most teenagers, dislike liste

Mamont248 [21]

B the phrasing of the question suggest a bias against classical music

that is the answer because they are assuming that no teens like classic music, which is just an opinion, which is bias :)

8 0

3 years ago

Please help so I can pass

lora16 [44]

Your answer would be F.

4 0

3 years ago