Answer:
0.105 = 10.5% probability that an accident results in a death.
Step-by-step explanation:
What is the probability that an accident results in a death?
5% of 60%(sunny)
25% of 20%(foggy)
12.5% of 20%(rainy)
So

0.105 = 10.5% probability that an accident results in a death.
Answer:
The range is from 147 to 153 orders per day
Step-by-step explanation:
orders varies by 2% means that orders can be LOWER THAN THE AVERAGE, or HIGHER THAN THE AVERAGE.
That is, by 2%.
First, we need to find the decimal of 2%, so
2/100 = 0.02
We multiply this with the average number of order, 150, to get the varying amount:
0.02 * 150 = 3
Thus, the range would be:
150 - 3 = 147
150 + 3 = 153
The range is from 147 to 153 orders per day
Well we are starting with a full pitcher(1)
1/4=2/8 & 1/8+2/8=3/8
then you subtract that from 1
1-3/8=5/8
Answer:
1 week= 7 days
number of days= 9
number of weeks= 1 week and 2 days
<em>hope it helps :)</em>
<em>please mark it the brainliest!</em>
Answer:
(A) -3 ≤ x ≤ 1
Step-by-step explanation:
The given function is presented as follows;
h(x) = x² - 1
From the given function, the coefficient of the quadratic term is positive, and therefore, the function is U shaped and has a minimum value, with the slope on the interval to the left of <em>h</em> having a negative rate of change;
The minimum value of h(x) is found as follows;
At the minimum of h(x), h'(x) = d(h(x)/dx = d(x² - 1)/dx = 2·x = 0
∴ x = 0/2 = 0 at the minimum
Therefore, the function is symmetrical about the point where x = 0
The average rate of change over an interval is given by the change in 'y' and x-values over the end-point in the interval, which is the slope of a straight line drawn between the points
The average rate of change will be negative where the y-value of the left boundary of the interval is higher than the y-value of the right boundary of the interval, such that the line formed by joining the endpoints of the interval slope downwards from left to right
The distance from the x-value of left boundary of the interval that would have a negative slope from x = 0 will be more than the distance of the x-value of the right boundary of the interval
Therefore, the interval over which <em>h</em> has a negative rate of change is -3 ≤ x ≤ 1