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2 years ago

10

Max's shop sells stuffed teddy bears. Today, Max sold 7 teddy bears for a total of $122.50. Which equation can be used to find b

, the cost of each bear?

1 answer:

Viefleur [7K]2 years ago

6 0

Answer: 17.50

Step-by-step explanation:

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Suppose a furniture manufacturer ships their products to distributors in pairs (so there are two items sent in each box). The we

Allushta [10]

Your answer is.............B. Negative.

3 0

2 years ago

The shorter leg is??????????

Leto [7]

The shorter leg is

10·SIN(30°) = 5

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3 years ago

A student receives test scores of 62, 83, and 91. This student's term project score is 88. Each test is worth 20% of the final g

miskamm [114]

Answer:

The student's current average score will be 69.2

Step-by-step explanation:

Let first test be TEST A: which is 20 of total and secures 62

Let second test be TEST B: which is 20 of the total marks and has secured 83.

Let third test be TEST C: which is 20 of total and has secured 91.

And now the TEST D which is 25 of total and has secured 88.

Therefore, by multipying across

${0.2}\times{62}$ = 12.4

${0.2}\times{83}$ = 16.6

${0.2}\times{91}$ = 18.2

${0.25}\times{88}$ =22

Now, by adding the scores to get the average score

We get, 69.2.

6 0

3 years ago

Tangent is positive in quadrants I and IV only.<br>True or False

zhannawk [14.2K]

Answer:

The statement is false

Step-by-step explanation:

we know that

$tan(x)=\frac{sin(x)}{cos(x)}$

The tangent function will be positive when the sine function and the cosine function have the same sign

so

In the first quadrant the tangent function is positive

In the third quadrant the tangent function is positive

so

The statement is false

6 0

3 years ago

Read 2 more answers

How can you analyze connections between linear equations and use them to solve problems

Alexeev081 [22]

Answer:

Step-by-step explanation:

One of the more obvious "connections" between linear equations is the presence of the same two variables (e. g., x and y) in these equations.

Assuming that your two equations are distinct (neither is merely a multiple of the other), we can use the "elimination by addition and subtraction" method to eliminate one variable, leaving us with an equation in one variable, solve this 1-variable (e. g., in x) equation, and then use the resulting value in the other equation to find the value of the other variable (e. g., y). By doing this we find a unique solution (a, b) that satisfies both original equations. Not only that, but also this solution (a, b) will also satisfy both of the original linear equations.

I urge you to think about what you mean by "analyze connections."

6 0

3 years ago