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docker41 [41]
2 years ago
11

Use this diagram and information given to find m_DFC.

Mathematics
1 answer:
Solnce55 [7]2 years ago
4 0
C c because that’s what I got
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Can anyone help please
Murrr4er [49]

Answer:

i dont know im sorry

Step-by-step explanation:

3 0
3 years ago
A football team plays in a large stadium. With a ticket price of ​$17​, the average attendance at recent games has been 50,000.
Verizon [17]

Answer:

a. N(x) = 50000 - 200x

b. R(x) = (50000-200x)(17+x)

Step-by-step explanation:

a. Given,

The the original price of each ticket = $ 17,

Also, the average attendance = 50,000

Let x be the number of times the original price of each ticket is increased by $ 1,

Also, for each​ $1 increase in the ticket​ price, attendance decreases by 200,

Thus, decrements in the attendance = 200x,

If N(x) represents the new average attendance,

Then,

N(x) = 50000 - 200x

Which is the required function,

b. Now,

Revenue = average attendance × price of each ticket

R(x) = N(x) × ( 17 + x )

⇒ R(x) = (50000-200x)(17+x)

Which is the required function.

3 0
3 years ago
A student solves the following equation and
Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}

\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}

\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)

\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)

\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)

as

  • \frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)
  • -\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a
  • \frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2

so equation becomes

3\left(a-2\right)-6a=a+2  

-3a-6=a+2

-3a-6+6=a+2+6

-4a=8

\mathrm{Divide\:both\:sides\:by\:}-4

\frac{-4a}{-4}=\frac{8}{-4}

a=-2

\mathrm{Verify\:Solutions}

\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}

\mathrm{Solve\:}\:a+2=0:\quad a=-2

\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2

\mathrm{Solve\:}\:a-2=0:\quad a=2

So the following points are undefined

a=-2,\:a=2

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0
3 years ago
PLEASE ANSWER ASAP -
Reika [66]

Answer:

The answer is $80 / $60

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
5w+60=52??????????????????????????????
Dima020 [189]

Subtract 60 from both sides to cancel it out. Now you have 5w=-8. Now divide 5 from both sides to cancel that out. Now you have w=-1.6.

---

hope it helps

6 0
2 years ago
Read 2 more answers
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