To calculate the midpoint,here's the formula : ((x1+x2)/2 , (y1+y2)/2)
thus, we have:
((10+(-4))/2 , (6+8)/2)
=(6/2 , 14/2)
=(3,7)

The coordinate for the midpoint is (3,7)

hope it helps!

7 0

4 years ago

Solve 12ds/w=CD for w.

denis23 [38]

Divide 12 on both sides
ds/w=cd/12
now multiply ds on both sides
w=cd/12ds

4 0

3 years ago

What is the factored form of x^12y^18+1

Black_prince [1.1K]

Answer: The required factored form of the given expression is

$(x^4y^6+1)(x^8y^{12}-x^4y^6+1).$

Step-by-step explanation: We are given to find the factored form of the following algebraic expression:

$E=x^{12}y^{18}+1.$

We will be using the following formula:

$a^3+b^3=(a+b)(a^2+ab+b^2).$

Now, we have

$E\\\\=x^{12}y^{18}+1\\\\=(x^4y^6)^3+1^3\\\\=(x^4y^6+1)\{(x^4y^6)^2-x^4y^6\times1+1^2\}\\\\=(x^4y^6+1)(x^8y^{12}-x^4y^6+1).$

Thus, the required factored form of the given expression is

$(x^4y^6+1)(x^8y^{12}-x^4y^6+1).$

4 0

3 years ago

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