All categories

1 year ago

A parallelogram has one angle that measures 106°. What are the measures of the other three angles in the parallelogram?

Mathematics

1 answer:

Katen [24]1 year ago

3 0

Answer:

74°,74° and 106°

Step-by-step explanation:

180 -106=74°

The two opposite interior angles=74°each

The other one=106°

You might be interested in

Y – 1 = 2(x – 2), solve for y

solmaris [256]

Answer:

y = 2x-3

Step-by-step explanation:

y – 1 = 2(x – 2)

Distribute

y-1 =2x-4

Add 1 to each side

y-1+1 = 2x-4+1

y = 2x-3

6 0

2 years ago

In Davidson Corporation, the first shift

IrinaVladis [17]

Answer:

Harley Davidson?

Step-by-step explanation:

7 0

2 years ago

Joe spends 18.75% of his working day washing cars. He spends 1.5 hours washing cars. How many total hours does he work per day?

insens350 [35]

Answer:

8 hours

Step-by-step explanation:

Joe spends 18.75% of his working day washing cars.

Joe spends 1.5 hours washing car.

Therefore 18.75% is equal to 1.5 hour.

18.75% = 1.5 hour

1% = 1.5 ÷ 18.75 = 0.08 hour

100% = 0.08 x 100 = 8 hours

4 0

3 years ago

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$