I neeeed help

If tan 0=3/4 find csc0

jasenka [17]

Answer:

tanθ = 3/4 p/b

using Pythagoras theorem

H² = P² + b²

H² = 3²+ 4²

H² = 25

H = 5

cosθ = B/H = 4/5

8 0

3 years ago

Five years ago, you invested $475 in corporate stock. You received dividends of $10 at the end of each quarter for two years. Yo

RUDIKE [14]

The rate of return earned on the investment of $475 five years ago in the corporate stock is 312.63%.

<h3>What is the rate of return?</h3>

The rate of return is the net gain or loss of an investment expressed as a percentage of the investment's initial cost.

It is given by the formula, R= {Vf - Vi}/{Vi} x 100.

Where:

R = Rate of return

Vf = final value, including dividends and interest

Vi = initial value

<h3>Data and Calculations:</h3>

Investment cost = $475

Dividends received:

1st two years = $80 ($10 x 8)

Three years = $180 ($15 x 12)

Total dividends received = $260 ($80 + $180)

Total revenue from sale = $1,700

Total proceeds = $1,960 ($1,700 + $260)

Total return = $1,485 ($1,960 - $475)

Rate of return = 312.63% ($1,485/$475 x 100)

Thus, the rate of return is 312.63%.

Learn more about calculating the rate of return at brainly.com/question/14220025

#SPJ1

8 0

1 year ago

A line that has a rise of -34 and a run of 20.

aleksandr82 [10.1K]

Answer:

$y=-1.7x-34$

Step-by-step explanation:

An equation of a line is given $y=mx+c$ , where m is the gradient or $\frac{Rise}{Run}$

The rise indicates the change in value of y (vertical change in the graph).

The run indicates the change in value of x (horizontal change in the graph).

Let point 1 of the graph be (x,y) = (0,-34) and point 2 be (x,y) = (20,0).

$m =\frac{Rise}{Run} \\ =\frac{-34}{20}\\ =-1.7$

Substitute point 1 into the graph to get the constant c.

$y=mx+c$

$-34=(-1.7)*(0)+c$

$c=-34$

∴ The equation of the line is, $y=-1.7x-34$

7 0

3 years ago

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home. Give the value of th

astra-53 [7]

Answer:

The value of the standard error for the point estimate is of 0.0392.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home.

This means that $n = 100, p = \frac{81}{100} = 0.81$

Give the value of the standard error for the point estimate.

This is s. So

$s = \sqrt{\frac{0.81*0.19}{100}} = 0.0392$

The value of the standard error for the point estimate is of 0.0392.

7 0

2 years ago

Someone please help me answer this question please and thank you.

fenix001 [56]

Students collect cards with equivalent mathematical or verbal expressions on them to make books of cards. A book is a group of 3 or 4 cards with either equivalent mathematical expressions or equivalent verbal expressions on them. When a player has at least 3 matching cards, he/she may lay down the book of cards. The object of the game is to be the first to get rid of all the cards in your hand.

Preparation: The teacher should print enough decks of cards so that one deck per group of 4 students can be distributed.

Shuffle the cards and deal out 7 cards to each player. Place the remaining cards in a pile (the draw pile) in the center of the table. Turn one card over to create the discard pile.

On his/her turn, each player will:

Either draw a card from the draw pile OR pick up the top card of the discard pile. (A player may only pick up the top card of the discard pile if by doing so it creates a book that the player can lay down immediately or it is a card that can be added to an existing book on the table.)

The player then examines his/her hand to see if there are any sets of three or four that can be laid down. If so, the cards are laid down on the table face up.

If the player does not have any groups to lay down, he/she may lay down a single card if that card can be added to another player’s book that has been laid on the table previously.

If the player can not put down a book or a single card to add to an existing book, then the player’s turn is over.

At the end of each turn the player must place a card on the discard pile. If this is the last card in his/her hand, then he/she is the winner!

Play moves to the left in a similar fashion until all the cars have been played or no other cards remain to be drawn and no player can go out. At that point, the player with the least number of cards in his/her hand is the winner.

Variation:

Students collect cards to make books but can only add a card to a book they have placed on the table themselves. At the end of the game, the player with the most books is the winner.

7 0

2 years ago