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Sphinxa [80]
2 years ago
5

Question 4 of 6

Mathematics
1 answer:
ra1l [238]2 years ago
7 0

The division law of exponents says that if b is a nonzero number and n and m are any numbers, then b^n/b^m=b^m-n so, the statement shown is false.

<h3>What are exponents?</h3>

The exponents of a number are defined as the representation of a number that shows how many times a number is multiplied by itself.

For this case we have the following expression:

\dfrac{ (b ^ n) }{(b ^ m)}

We have to:

b = number other than zero

m, n = any number

By properties of exponents we have:

\dfrac{ (b ^ n) }{(b ^ m)} = b ^{ (n-m)}

Therefore, we have that the statement shown is false.

Learn more about exponentiation here:

brainly.com/question/26938318

#SPJ1

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Arwen uses an eye dropper that produces drops that has a volume of 1/8 milliliter to fill 30 milliliter test tube. How many drop
oksian1 [2.3K]
To answer this question, you need to know how many drops go into atheism test tube.

Each drop is 1/8 milliliter. The test tube is 30 milliliter.

So, divide 30 by 1/8 to see how many times 1/8 goes into 30.

30 divided by 1/8 = 30 times 8 = 240

It takes 240 drops (that's a lot!) to fill up the test tube.

Hope this helps!
4 0
3 years ago
13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult
Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that \frac{ab}{m} is and integer.

As m= vb, then \frac{m}{b} is an integer, lets say \frac{m}{b}=v; and as m=ua, then \frac{m}{a}=u.

So \frac{ab}{m}v=\frac{ab}{m}\frac{m}{b}=a, so \frac{ab}{m} divides a; on the other hand, \frac{ab}{m}u=\frac{ab}{m}\frac{m}{a}=b, so \frac{ab}{m} divides b. From this we can conclude that \frac{ab}{m} is a common divisor of a and b.

4 0
3 years ago
11.
Mrrafil [7]

Answer:

2 should be distributed as 2y + 16; y = 8

Step-by-step explanation:

We have to distribute 2, then:

Now we have to sum (-2y) in both sides of the equation:

Finally we have to divide both sides of the equation in 2:

Then the answer is 2 should be distributed as 2y + 16; y = 8

Hope this helps.

8 0
3 years ago
Which set of transformations have been performed on triangle ABC to form triangle A′B′C′? (1 point)
Murrr4er [49]

Answer:

The answer is dilation by a scale factor of 2 followed by reflection about the y- axis.

Step-by-step explanation:

3 0
3 years ago
What is the measure of &lt;1?
QveST [7]

Answer:

79°

Step-by-step explanation:

Angle one is an alternate exterior angle to the angle that has 79° in it so angle one will equal 79°.

3 0
3 years ago
Read 2 more answers
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