Answer:
a) 
b) 
c) 
Step-by-step explanation:
<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.
This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.
Then write the polynomial in factored form.

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.
<u>For question b, do the same procedure</u>.
Degree: 3
Zeros: -5/2, 4/5, 6.
The factors are

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
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
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
<u>Finally for the question c we have</u>
Degree: 5
Zeros: -3, 1, 4, -1
Multiplicity 2 in -1

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
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
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
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
Answer:
2/21
Step-by-step explanation:
you square 4/7 to get 16/49 then use keep change flip
you now have 16/49 times 7/24 then multiply
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
sin²x + cos²x = 1 , then
sin²x = 1 - cos²x and cos²x = 1 - sin²x
Consider the left side
← expand numerator/denominator using FOIL
=
= 
= 
= 
= cot²A = right side , thus proven
#15(A)
First Bike
$380 - $190 ($380 * 0.50) = $190
2nd Bike
$380 - $114 ( $380 * 0.30) = $266
$266 - $53.20 ($266 * 0.20) = $212.80
#15 (B)
Eliza should buy the first bike because it is cheaper. $190 < $212.80
#16
$57 + $28.50 ($57 * .50) = $85.50
The answer would be 3x i believe
hope this helps! if it doesn't, let me know in the comments! have a great day!