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2 years ago

Simplify the expression so there is only one positive power for each base.

Mathematics

2 answers:

stealth61 [152]2 years ago

8 0

They are like this because

mixas84 [53]2 years ago

6 0

Answer:

hhdbbdbjhbfdbds

Step-by-step explanation:

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The difference between the squares of two numbers is 20. three times the square of the first number increased by the square of t

Mashcka [7]

We need a system of equations to solve this. "Difference" is to subtract, and we are taking this difference of the 2 squared unknowns to be 20. That equation is $x^{2} -y^2=20$ . Our "first number is x^2, so 3 times that is 3x^2. "Increased by" is adding to that first number. What we are adding is the second number. The second equation is $3x^2+y^2=124$ . Let's solve the first equation for x^2: $x^2=y^2+20$ and sub that value for x^2 into the second equation. $3(y^2+20)+y^2=124$ and $3y^2+60+y^2=124$ . Subtract 60 from both sides and combine the y^2 terms to get $4y^2=64$ . Divide both sides by 4 to get y^2 = 16 and y = 4. Let's go back now and solve for x. We will use the fact that y^2 = 16 to solve for x^2 and then take the square root of it. $x^2-16=20$ , x^2 = 4, so x = 2. Your solutions are x = 2 and y = 4. There you go!

8 0

3 years ago

Can someone help me solve this equation for 3/4w-1/2w-4= 12

muminat

Multiply both sides by 4
3w-2w-16=48
Combine like terms
w-16=48
Add 16 on both sides
w=64

3 0

3 years ago

HELP!

andre [41]

Answer:

Step-by-step explanation:

Distribute 10 in the equation

10 x 3 + 10 x 4 = 70

5 0

2 years ago

Read 2 more answers

He vertices of square pqrs are p -4,0 q 4,3 r 7,-5 and s -1,-18.Show that the diagonals of square pqrs are congruent perpendicul

Anit [1.1K]

Answer:

Step-by-step explanation:

The vertices of the square given are P(-4, 0), Q(4, 3), R(7, -5) and, S(-1, -18)

For this diagonal to be right angle the slope of the diagonal must be m1=-1/m2

So let find the slope of diagonal 1

The two points are P and R

P(-4, 0), R(7, -5)

Slope is given as

m1=∆y/∆x

m1=(y2-y1)/(x2-x1)

m1=-5-0/7--4

m1=-5/7+4

m1=-5/11

Slope of the second diagonal

Which is Q and S

Q(4, 3), S(-1, -18)

m2=∆y/∆x

m2=(y2-y1)/(x2-x1)

m2=(-18-3)/(-1-4)

m2=-21/-5

m2=21/5

So, slope of diagonal 1 is not equal to slope two

This shows that the diagonal of the square are not diagonal.

But the diagonal of a square should be perpendicular, this shows that this is not a square, let prove that with distance between two points

Given two points

(x1,y1) and (x2,y2)

Distance between the two points is

D=√(y2-y1)²+(x2-x1)²

For line PQ

P(-4, 0), Q(4, 3)

PQ=√(3-0)²+(4--4)²

PQ=√(3)²+(4+4)²

PQ=√9+8²

PQ=√9+64

PQ=√73

Also let fine RS

R(7, -5) and, S(-1, -18)

RS=√(-18--5)+(-1-7)

RS=√(-18+5)²+(-1-7)²

RS=√(-13)²+(-8)²

RS=√169+64

RS=√233

Since RS is not equal to PQ then this is not a square, a square is suppose to have equal sides

But I suspect one of the vertices is wrong, vertices S it should have been (-1,-8) and not (-1,-18)

So using S(-1,-8)

Let apply this to the slope

Q(4, 3), S(-1, -8)

m2=∆y/∆x

m2=(y2-y1)/(x2-x1)

m2=(-8-3)/(-1-4)

m2=-11/-5

m2=11/5

Now,

Let find the negative reciprocal of m2

Reciprocal of m2 is 5/11

Then negative of it is -5/11

Which is equal to m1

Then, the square diagonal is perpendicular

6 0

3 years ago

Jean gets an allowance of $15 each month plus an extra $2 for each chore she completes around the house. How much allowance will

katovenus [111]

The answer is 2x + 15 dollars.

5 0

3 years ago