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Ivahew [28]
3 years ago
9

What is the answer for this MATH PROBLEM???please explain how you got the answer, thank you

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
7 0
The answer is e, 3 3/4

if you add 3/4+3/4+3/4+3/4+3/4 (five times for the five batches), or did 3/4 * 5, you would get 15/4, which simplifies to 3.75, or 3 3/4
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What is the image of (-1,8) after translation right 1 units and up 2 units
Vladimir79 [104]

Answer:(0,10)

Step-by-step explanation: Im pretty sure because of subtracting 1 from the -1 in your x value and adding 2 to the 8 in you Y value

4 0
3 years ago
With a line 7 cm long. Use a set square and a ruler and draw perpendicular lines at both ends
Setler79 [48]

Answer:

See Explanation

Step-by-step explanation:

According to the Question,

Steps of construction:

  • Step I - Draw a line segment AB = 7 cm with the help ruler.
  • Step II - with vertex A, by using compass take more than half of AB and draw arcs, one on each side of AB.
  • Step III - with vertex B, by using a compass with the same length, cut the previous arcs at X and Y respectively.
  • Step IV - with help of the ruler join the points X and Y Thus XY is the perpendicular bisector of line AB.

(For Diagram please find in attachment)

5 0
3 years ago
Pls help me in this i really need help :( :)
Andrews [41]

Hello and Good Morning/Afternoon:

<u>Let's take this problem step-by-step:</u>

<u>First off, let's write the line in point-slope form:</u>

  \rm \hookrightarrow (y-y_0)=m(x-x_0)

  • (x₀, y₀) any random point on the line
  • 'm' is the value of the slope

<u>Let's calculate the slope:</u>

 \rm \hookrightarrow Slope = \frac{y_2-y_1}{x_2-x_1}

  • (x₁, y₁): any random point on the line                                     ⇒   (-2, -6)
  • (x₂,y₂): any random point on the line that is not (x₁, y₁)         ⇒   (2, -3)

                 \rm \hookrightarrow slope = \frac{-3--6}{2--2} =\frac{3}{4}

<u>Now that we found the slope, let's put it into the point-slope form</u>

  ⇒ we need (x₀, y₀) ⇒ let's use (2,-3)

     (y-(-3))=\frac{3}{4} (x-2)\\y+3=\frac{3}{4} (x-2)

<u>The equation, however, could also be put into 'slope-intercept form'</u>

     ⇒ gotten by isolating the 'y' variable to the left

          y = \frac{3}{4}x-\frac{9}{2}  

<u>Answer:</u>y = \frac{3}{4}x-\frac{9}{2} or y+3=\frac{3}{4} (x-2)

   *<em>Either equations work, put the one that you are the most familiar with</em>

Hope that helps!

#LearnwithBrainly

5 0
2 years ago
Find the equation of the line through (8,−6) which is perpendicular to the line y=x3−7.
ycow [4]

Answer:

y = (-1/3)(x + 10)

Step-by-step explanation:

The slope of the new (perpendicular) line is the negative reciprocal of the slope of the given line, which appears to be 3.  Thus, the perpendicular line has the slope -1/3.

Using the slope-intercept form y = mx + b, and substituting the givens, we obtain:

y = mx + b    =>    -6 = (-1/3)(8) + b, or

-6 = -8/3 + b.  We must solve for the y-intercept, b:

Multiplying all three terms by 3 removes the fraction:

-18 = -8 + 3b.  Thus, -10 = 3b, and so b must be -10/3.

The desired equation is    

y = (-1/3)x - 10/3, or

y = (-1/3)(x + 10)

8 0
3 years ago
Help this question why s really hard
Kitty [74]

Answer:

12 2/3

Step-by-step explanation:

I'm too lazy to give an explanation. Hope this helped though.

7 0
3 years ago
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