Question

What are the solutions to the quadratic equation below in factored form?

Answer 1

• (10x+5)(11x-44)=0
• 10x(11x-44)+5(11x-44)=0
• 110x²-440x+55x-220=0
• 110x²-385x-220=0

On solving

• x=-1/2 or x=4

Answer 2

Answer:

D.) x = − ½, x = 4

Explanation:

$\rightarrow \sf (10x + 5)(11x - 44) = 0$

set the factors to zero

$\rightarrow \sf 10x + 5 = 0, \ 11x - 44 = 0$

exchange the sides

$\rightarrow \sf 10x = -5, \ 11x = 44$

exchange the sides

$\rightarrow \sf x = -\dfrac{5}{10} , \ x = \dfrac{44}{11}$

simplify the following

$\rightarrow \sf x = -\dfrac{1}{2} , \ x =4$