Answer:
13.98 in²
Step-by-step explanation:
I don't understand it, either.
Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.
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The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.
The area of a segment is given by the formula ...
A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.
Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...
A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²
Rounded to hundredths, this is ...
≈ 13.98 in²
How do we graph anything? Make a table of values for x and y and then plot each point. After plotting each point on the xy-plane, connect each point with a straight line or curve (depending on the function).
In this case, we must first isolate y.
y = (-4/3)x + 8y
y - 8y = (-4/3)x
-7y = (-4/3)x
y = (-4/3)x ÷ (-7)
y = (4/21)x
Now follow the steps above.
in STR,
ST=SR
therefore, t=r(angles opposite equal sides of a triangle are equal)
T=73
C+73+73=180(ASP of triangle)
C=34
Answer:
Step-by-step explanation:
The given expression is :
It can be solved as follows :
So, the solution of the given expression is equal to .
The relationship between Sabir and calories he burns can be modeled using a linear function given by:
y=ax+b
where
a=slope
b=y-intercept
from the graph, the slope will be given as follows:
taking points (3,15) and (12,60)
a=(60-15)/(12-3)=5 calories/minute
thus using the slope and a point (3,15) the equation will be:
a(x1-x)=(y1-y)
plugging the values we obtain:
5(x-3)=y-15
5x-15=y-15
thus
y=5x
thus the equation is:
y=5x
