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grandymaker [24]
3 years ago
10

How do you solve the equation -3 1/3 = -1/2g

Mathematics
1 answer:
Arturiano [62]3 years ago
3 0

g=\frac{20}{3}

Solution:

Given expression is -3\frac{1}{3}=\frac{-1}{2}g.

To solve the given expression:

Let us first convert the mixed fraction into improper fraction.

⇒ -3\frac{1}{3}=\frac{-1}{2}g

⇒ -\frac{(3\times 3 )+1}{3}=\frac{-1}{2}g

⇒ -\frac{10}{3}=\frac{-1}{2}g

Do cross multiply on both sides of the equation.

⇒ -10\times2=(-1\times3)g

⇒ -20 = -3g

⇒ \frac{-20}{-3}=g

Both minus in the numerator and denominator are cancelled.

⇒ \frac{20}{3}=g

Hence, g=\frac{20}{3}.

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A store owner had 42 pounds of almonds, 38.5 pounds of walnuts, and 62.5 pounds of peanuts. If the owner splits the peanuts equa
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Here is your answer

12.5 pounds

REASON:

Weight of total peanuts= 62.5 pounds

It is splitted into equally into 5 jars.

So,

Pounds of peanut each jar contains= Total weight/No. of jars

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HOPE IT IS USEFUL

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Tcecarenko [31]
Answer:
If this is what your looking for, the answer may be:
-4y + 12
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5 0
2 years ago
(2,3), (4,-7) midpoint
Gnoma [55]

Answer:

(3, -2)

Step-by-step explanation:

2+4 = 6

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8 0
3 years ago
PLEASE SHOW WORK
CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

V = \dfrac{\pi}{3}r^2h

Taking the derivative of V with respect to time, we get

\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)

\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)

Since r is always equal to h, we can set

\dfrac{dr}{dt} = \dfrac{dh}{dt}

so that our expression for dV/dt becomes

\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)

\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}

Solving for dh/dt, we get

\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}

\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})

\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}

7 0
3 years ago
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