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Oliga [24]
2 years ago
10

Trevor tosses a coin then rolls a die

Mathematics
1 answer:
schepotkina [342]2 years ago
7 0

The probability of tossing heads and not rolling 5 is 31/32.

Let us assume a coin is fair and 2-sided.

A coin usually flips heads or tails.

Then to flip heads or tails equals  1/2

​ Consider flipping a coin 5 times.

Since a coin flip has two outcomes, then a coin flip 5 times has 2

5 =32 outcomes.

We may show the outcomes, e.g. use sample space S.

Then (1)S=(H,H,H,H,H),(H,H,H,H,T),…,(T,H,H,H,H),(T,T,T,T,T)

It must follow ∣S∣=32.

A helpful way to see may be S=H, T 5=H, Tx…Hx, T.

<h3>What is the formula for probability?</h3>

P(S)=1-P(A)

If you see the complement of at least 1 tail means 0 tails or 5 heads, then we must surely see 1 outcome, e.g. all heads.

Then it must follow at least one tail that has 31 outcomes,e.g.32–1=31.

To find or compute the probability, then fevorable possible in outcomes.

It means 31/32,

P(E)=1– 32/1= 32/31

​To learn more about the probability visit:

brainly.com/question/24756209

#SPJ1

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A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte
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Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:

H_0: \mu \leq 0.7

At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:

H_1: \mu > 0.7

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7

A survey of 35 people was conducted to compare their self-reported height to their actual height.

This means that n = 35

From the sample, the mean difference was 0.95, with a standard deviation of 0.44.

This means that X = 0.95, s = 0.44

Calculate the test statistic

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}

t = 3.36

The test statistic is t = 3.36.

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3 years ago
What is 40% of 40 please show work
tino4ka555 [31]

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Answer:

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Step-by-step explanation:

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This is Right answer

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Answer:

Step-by-step explanation:

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