All categories

2 years ago

What is the domain of the ordered pairs?

Mathematics

1 answer:

BigorU [14]2 years ago

3 0

Answer:

b. {-3, -1, 2}

Step-by-step explanation:

An ordered pair is a pair of elements written as (x, y) where the first element is the input value and the second element is the output value.

The domain is the set of input values (x-values)

The range is the set of output values (y-values)

Therefore, for the given ordered pairs (-1, 0), (2, 4) and (-3, 6)

Domain: {-3, -1, 2}

Range: {0, 4, 6}

You might be interested in

Alex got 9 hits in his first 22 at bats. If his hitting rate remains constant, how many at bats would he have to have to reach 5

nikklg [1K]

Answer:

122.2222 repeating

Step-by-step explanation:

3 0

3 years ago

If you are dealt 3 cards from a shuffled deck of 52 cards, find the probability that all 3 cards are queens.

oksian1 [2.3K]

Answer:

I think the answer is 3/52

3 0

3 years ago

NEED HELP ASAP!

Nana76 [90]

Answer:

Step-by-step explanation:

bruh

4 0

4 years ago

Expand (2x+2)^6 How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

1 year ago

I must be s.tupid but someone plzzzzzzzz help!

Gala2k [10]

Answer:

Step-by-step explanation:

8.5 is also 8 and 1/2, it just has negative signs infront

3 0

3 years ago