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sveticcg [70]
3 years ago
11

If AB = 18, BC = 10, and CA = 13, list the angles of ABC in order from smallest to largest.

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
5 0
Angle A is smallest
Then angle B
And angle C is largest

Should be correct... it may vary depending on where A, B, and C are located on the triangle
Novosadov [1.4K]3 years ago
5 0

Answer: ∠A < ∠B < ∠C

Step-by-step explanation:

Given:  In Δ ABC

AB = 18, BC = 10, and CA = 13

We can see that

10<13<18

Thus, BC < CA < AB   ........................(1)

We know that in triangles the larger angle to opposite to the largest side if larger.

Since, ∠A is opposite to BC

∠B is opposite to CA

∠C is opposite to AB

Therefore, from (1), we have

∠A < ∠B < ∠C

Thus, the angles of ΔABC in order from smallest to largest will be

∠A < ∠B < ∠C

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Easy 50 points for one question
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Answer:

I believe its C

Step-by-step explanation:

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