C should be -10
Hope this helps
The correct answer is right.
An acute one would have all three acute, while an obtuse one would have at least one obtuse angle.
X^2 + y^2 - 16y + 39 = 0
<span>-x^2 + y^2 - 9 = 0 </span>
<span>----------------------------------- </span>
<span>2y^2 - 16y + 30 = 0 iff </span>
<span>y^2 - 8y + 15 = 0 iff </span>
<span>(y - 3)(y - 5) = 0 iff </span>
<span>y = 3 or y = 5. </span>
<span>Now plug in y value into any of the given equations (the second one is easier) to find respective x values. </span>
<span>y^2 - x^2 - 9 = 0 </span>
<span>(3)^2 - x^2 - 9 = 0 iff </span>
<span>9 - x^2 - 9 = 0 iff </span>
<span>x^2 = 0 iff </span>
<span>x = 0 </span>
<span>(0, 3) </span>
<span>y^2 - x^2 - 9 = 0 </span>
<span>(5)^2 - x^2 - 9 = 0 iff </span>
<span>25 - x^2 - 9 = 0 iff </span>
<span>16 - x^2 = 0 iff </span>
<span>(4 - x)(4 + x) = 0 iff </span>
<span>x = 4 or x = -4 </span>
<span>(4, 5), (-4, 5) </span>
<span>We have three points of intersection, which are (0, 3), (4, 5), and (-4, 5).</span>
I hope this helps you
g (2)=2^2-7
g (2)= -3
fog (2)=f (g (2))=f (-3)
f (-3)=2. (-3)+1
f (-3)= -5
