What are the zeros of the quadratic function f(x)=8^2-16-15

he local newspaper has letters to the editor from 30 people. If this number represents 2% of all of the newspaper's readers, ho

marta [7]

Answer: 1500 readers
explanation: all readers take up 100%
100/50=2
100% / 50 = 2%
2% x 50 = 100%
30 x 50 = 1500 readers

7 0

3 years ago

Celia has some cakes.

Vadim26 [7]

The carrot cakes are the fraction of the cake given by $1 - \frac{6}{7}$ multiplied by $\frac{1}{3}$

The fraction of the cakes that are carrot cakes is $\underline {\dfrac{1}{21}}$

<h3>How are the cakes evaluated as fractions?</h3>

The fraction of the cake that are chocolate cake = $\dfrac{2}{3}$

The fraction of the remaining cake that cheesecakes = $\dfrac{6}{7}$

The rest of the cakes = carrot cakes

Required:

The fraction of the cake that are carrot cakes

Solution:

The fraction of the cakes that are not chocolate cake = $1 - \dfrac{2}{3} = \mathbf{ \dfrac{1}{3}}$

The fraction of the remaining cakes that are cheesecake = $\dfrac{6}{7} \times \dfrac{1}{3} = \mathbf{ \dfrac{6}{21}}$

The fraction of the cake that are carrot cake = $\dfrac{1}{3} - \dfrac{6}{7} \times \dfrac{1}{3} = \mathbf{\dfrac{1}{21}}$

The fraction of the cakes that are carrot cake is $\underline{\dfrac{1}{21}}$

Learn more about fractions here:

brainly.com/question/3840488

5 0

1 year ago

Solve. -5/8c = 20 A. -34 B. -32 C. 32 D. 34

aleksandrvk [35]

$- \frac{5}{8} c$ = 20

First, simplify $\frac{5}{8} c$ to $\frac{5c}{8}$ / Your problem should look like: $- \frac{5c}{8}$ = 20
Second, multiply both sides by 8. / Your problem should look like: -5c = 160
Third, divide both sides by -5. / Your problem should look like: c = $\frac{160}{-5}$
Fourth, simplify $\frac{160}{-5}$ to $-\frac{160}{5}$ / Your problem should look like: c = $-\frac{160}{5}$
Fifth, simplify $\frac{160}{5}$ to 32. / Your problem should look like: c = -32

Answer: B) -32

3 0

3 years ago

If x = 7, which equations are true?

kykrilka [37]

Step-by-step explanation:

We need the attatchments..

6 0

2 years ago

Read 2 more answers

Find a if the point (3,a) is on the line that passes through (-2,7) and (5,-3).

saw5 [17]

Your first step is to find the slope of the line. You can find that using the formula $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ . Plug the x- and y- values from the coordinate pairs into the formula.

 $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ Plug in the coordinates
 $\frac{-3 - 7}{5 - (-2)}$ Cancel out the double negative
 $\frac{-3 - 7}{5 + 2}$ Add and subtract
 $\frac{-10}{7}$

Next, you can use the same formula to find a by setting it against the slope you just found.

slope = $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ Plug in the values
$\frac{-10}{7}$ = $\frac{7 - a}{-2 - 3}$ Subtract
$\frac{-10}{7}$ = $\frac{7 - a}{-5}$ Multiply both sides by 7
-10 = $\frac{7(7 - a)}{-5}$ Use the Distributive Property
-10 = $\frac{49 -7a}{-5}$ Multiply both sides by -5
50 = 49 - 7a Subtract 49 from both sides
1 = -7a Divide both sides by -7
$-\frac{1}{7}$ = a Switch the sides to make it easier to read
a = $-\frac{1}{7}$

8 0

2 years ago