What are the zeros of the quadratic function f(x)=8^2-16-15
1 answer:
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Okay, so I really hope that you can read all my work. I just spent the last 45 mins doing this problem as neatly as possible with as much detail as possible. So, I really hope my work doesn't confuse you.
My Final Answers were:
JI= 40 units (found using the Pythagorean theorem)
IM= 66.66 units = 66 and 2/3rds (found by dividing the length of JL by the cosine of ∠JIM )
LM=42.66 units = 42 and 2/3rds (found by IM= 24+LM; solve for LM since we know IM=66.66)
JM= 53.33 units= 53 and (1/3rd) (found by using the Pythagorean theorem; this time using JI as "a" and IM as c)
Hope this helped and all made sense!
(Pythagorean theorem is a²+b²=c²)
My Final Answers were:
JI= 40 units (found using the Pythagorean theorem)
IM= 66.66 units = 66 and 2/3rds (found by dividing the length of JL by the cosine of ∠JIM )
LM=42.66 units = 42 and 2/3rds (found by IM= 24+LM; solve for LM since we know IM=66.66)
JM= 53.33 units= 53 and (1/3rd) (found by using the Pythagorean theorem; this time using JI as "a" and IM as c)
Hope this helped and all made sense!
(Pythagorean theorem is a²+b²=c²)