Answer:
Number of $8 tickets sold = 210
Number of $10 tickets sold = 280
Number of $12 tickets sold = 70
Step-by-step explanation:
The number of ticket sold is 560 tickets .
Total number of ticket sold = 560 tickets
The prices varies as $8, $10 and $12.
The total income from the ticket sold = $5320
Let
number of $8 ticket sold = a
number of $10 ticket sold = b
number of $12 ticket sold = c
a + b = 7c
Therefore,
8a + 10b + 12c = 5320
a + b + c = 560
7c + c = 560
8c = 560
divide both sides by 8
c = 560/8
c = 70
Insert the value of c in the equations below
8a + 10b + 12c = 5320
8a + 10b + 12(70) = 5320
8a + 10b + 840 = 5320
8a + 10b = 5320 - 840
8a + 10b = 4480...........(i)
a + b + c = 560
a + b + 70 = 560
a + b = 560 - 70
a + b = 490...............(ii)
8a + 10b = 4480...........(i)
a + b = 490...............(ii)
a = 490 - b
insert the value of a in equation(i)
8(490 - b) + 10b = 4480
3920 - 8b + 10b = 4480
3920 + 2b = 4480
2b = 4480 - 3920
2b = 560
b = 560/2
b = 280
insert the value of b in equation (ii)
a + b = 490...............(ii)
a + 280 = 490
a = 490 - 280
a = 210
Number of $8 tickets sold = 210
Number of $10 tickets sold = 280
Number of $12 tickets sold = 70
