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Semenov [28]
2 years ago
13

Please help me with this.

Mathematics
1 answer:
Valentin [98]2 years ago
8 0

The correct proportion of the corresponding sides is 2 : 3

<h3>How to determine the proportion?</h3>

From the question, we understand that the shapes are similar.

This means that:

Ratio = GHIJ : KLMN

From the figure, we have:

GH = 6 and KL = 9

So, we have:

Ratio = 6 : 9

Simplify the ratio

Ratio = 2 : 3

Hence, the correct proportion of the corresponding sides is 2 : 3

Read more about similar shapes at:

brainly.com/question/14285697

#SPJ1

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"<span>y + 5 ≥ 4" is the one inequality among the following choices that has been shown. The correct option among all the options that are given in the question is the third option or option "C". The other choices are incorrect and can be easily avoided. I hope that this is the answer that has actually come to your desired help.</span>
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3 years ago
What is the length of segment
chubhunter [2.5K]

Answer: square root of 53

Step-by-step explanation:

did the math

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2 years ago
PLEASE HELP
enot [183]
The triangles are shown to be similar, therefore

\displaystyle \frac{54}{12} = \frac{x}{2} \\ \\&#10;x = 2 \cdot \frac{54}{12} \\&#10;x = 9

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8 0
3 years ago
Read 2 more answers
Y=1/3x what is the slope
Karolina [17]

Answer:

Slope = \frac{1}{3}

Step-by-step explanation:

The equation for finding slope is:

y = mx+b

In the equation, m is the slope, x is the x-intercept, and b is the y-intercept. The number next to x is ALWAYS the slope.

Your equation:

y = \frac{1}{3} x

The number(fraction) next to x is \frac{1}{3}. Therefore, your answer will be \frac{1}{3}

3 0
3 years ago
What is the value of sin-1(1)? negative startfraction pi over 2 endfraction 0 startfraction pi over 2 endfraction π
mariarad [96]

The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

<h3>What is the value of sin (π/2)?</h3>

The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.

Suppose the value of this function is <em>x</em>. Thus,

x=\sin^{-1}(1)

Solve it further,

\sin(x)=(1)              ......1

The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,

\sin\dfrac{\pi}{2}=-\sin\left(-\dfrac{\pi}{2}\right)=1

Put this value in the equation 1,

\sin(x)=\sin\left(\dfrac{\pi}{2}\right)=-\sin\left(-\dfrac{\pi}{2}\right)

Thus, the range will be,

\left(\dfrac{\pi}{2},-\dfrac{\pi}{2}\right)

Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

Learn more about the sine values here;

brainly.com/question/10711389

3 0
3 years ago
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