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Alex777 [14]
2 years ago
12

I need help with this geometry question

Mathematics
1 answer:
UNO [17]2 years ago
6 0

Answer:

radius ≈ 15.5

Step-by-step explanation:

the radius is RS

the angle between a tangent and the radius at the point of contact is 90°

then Δ RST is a right triangle

using Pythagoras' identity in the right triangle.

the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then

RS² + ST² = RT² ( substitute values )

RS² + 7² = 17²

RS² + 49 = 289 ( subtract 49 from both sides )

RS² = 240 ( take square root of both sides )

RS = \sqrt{240} ≈ 15.5 ( to 1 dec. place )

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find a formula for the nth term of the arithmetic sequence the first term is -2 and the common difference is 8
Rudiy27

Answer:

a(n) = -2 + 8(n - 1)

Step-by-step explanation:

General formula is a(n) = a(1) + d(n - 1), where d is the common difference.

Here a(n) = -2 + 8(n - 1)

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How to integrate with steps:<br><br> (4x2-6)/(x+5)(x-2)(3x-1)
joja [24]

\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx

You have a rational expression whose numerator's degree is smaller than the denominator's. This tells you you should consider a partial fraction decomposition. We want to rewrite the integrand in the form

\dfrac{4x^2-6}{(x+5)(x-2)(3x-1)}=\dfrac a{x+5}+\dfrac b{x-2}+\dfrac c{3x-1}

\implies4x^2-6=a(x-2)(3x-1)+b(x+5)(3x-1)+c(x+5)(x-2)

You can use the "cover-up" method here to easily solve for a,b,c. It involves fixing a value of x to make 2 of the 3 terms on the right side disappear and leaving a simple algebraic equation to solve for the remaining one.

  • If x=-5, then 94=112a\implies a=\dfrac{47}{56}
  • If x=2, then 10=35b\implies b=\dfrac27
  • If x=\dfrac13, then -\dfrac{50}9=-\dfrac{80}9c\implies c=\dfrac58

So the integral we want to compute is the same as

\displaystyle\frac{47}{56}\int\frac{\mathrm dx}{x+5}+\frac{10}{35}\int\frac{\mathrm dx}{x-2}+\frac58\int\frac{\mathrm dx}{3x-1}

and each integral here is trivial. We end up with

\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx=\frac{47}{56}\ln|x+5|+\frac27\ln|x-2|+\frac5{24}\ln|3x-1|+C

which can be condensed as

\ln\left|(x+5)^{47/56}(x-2)^{2/7}(3x-1)^{5/24}\right|+C

7 0
3 years ago
HELP 50pts And Brainleist. I need the Answers ...
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Let us assume that the first company the cab flat rate is 5$ and the cap driver charges 2$ per mile .for the second company the cab flat rate is 3$ and the cab driver charges 3$ per mile.
a. the company charges per ride at least 5$ and an extra 2$ per mile
b.the equation we will choose is slope intercept since we know the
y-intercept which is the cab flat rate .
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where
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b:is the y-intercept
y:total amount
x. is the milage
total amount=2x+5.
c.the slope will be 2$ which is the change in amount per mile.the y-intercept will be the cab's flat rate.
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3 years ago
A test has 20 questions. If Peter gets 80% correct, how many questions did Peter miss?
Oduvanchick [21]

Answer:

4

Step-by-step explanation:

20 x 0.80

16 - 20

3 0
3 years ago
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