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2 years ago

13

do you guys know what this is? the answer should have y = answer. When I tried to solve it, I got zero. Is that correct? Here's

the problem: 0.5y-2 2/5=1/2y+2.4

1 answer:

dimaraw [331]2 years ago

4 0

Answer:

The answer is NO SOLUTION -> there are no values of y that make the equation true.

Step-by-step explanation:

Hope this helps :)

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In a 4 day period, a delivery person delivered the following number of

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2 years ago

A certain fraction is greater than 2. The denominator is 8. What must be true about the numerator?

Volgvan

Answer:

The numerator must be greater than 16

Step-by-step explanation:

We are told that a certain fraction is greater than 2. Thus, if the numerator and denominator are x and y respectively, then we have;

x/y > 2

We are further told that the denominator is 8.

Thus;

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Thus,the numerator must be greater than 16.

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

XYZ has coordinates X(2, 3), Y(1,4), and Z(8,9). A translation maps X to X'(4,7). What are the coordinates for Y' and Z' for thi

Rashid [163]

Answer:

The coordinates are $Y'(x,y) = (3, 8)$ and $Z'(x,y) = (10, 13)$ .

Step-by-step explanation:

First, we have to derive an expression for translation under the assumption that each point of XYZ experiments the same translation. Vectorially speaking, translation from X to X' is defined by:

$X'(x,y) = X(x,y) + T(x,y)$ (1)

Where $T(x,y)$ is the vector translation.

If we know that $X(x,y) = (2,3)$ and $X'(x,y) = (4,7)$ , then the vector translation is:

$T(x,y) = X'(x,y)-X(x,y)$

$T(x,y) = (4,7) - (2,3)$

$T(x,y) = (2, 4)$

Then, we determine the coordinates for Y' and Z':

$Y'(x,y) = Y(x,y) + T(x,y)$

$Y'(x,y) = (1,4) + (2,4)$

$Y'(x,y) = (3, 8)$

$Z'(x,y) = Z(x,y) + T(x,y)$

$Z'(x,y) =(8,9) + (2,4)$

$Z'(x,y) = (10, 13)$

The coordinates are $Y'(x,y) = (3, 8)$ and $Z'(x,y) = (10, 13)$ .

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2 years ago