This is the concept of algebra, given that the length of the rectangle is 5x-2 and the width is 3x+1, the perimeter is 2(5x-2)+2(3x+1). To get the total distance Zohar needs to cut with the scissors, we substitute the value of x=4 in the expression for perimeter. Hence we shall have:
2(5x-2)+2(3x+1)
=2(5*4-2)+2(3*4+1)
=2(20-2)+2(12+1)
=2(18)+2(13)
=36+26
=62 cm
The answer is 62 cm
Answer:
length :16cm
wide :20cm
We have
Area of inner frame :16*20=320cm²
For
Total area =464cm²
(20+2x)(16+2x)=464cm²
320+32x+40x+4x²=464cm²
4x²+72x+320-464=0
4x²+72x-144=0
4(x²+18x-36)=0
x²+2.9.x+9²=9²+36
(x+9)²=117
x+9=√117
x=10.81-9
x=1.82[approximately]
So
<u>width of frame;20cm+1.82+1.82=23.64cm</u>
<u>length: 16+1.82+1.82=19.64cm</u>
Here length is smaller than breadth.
Answer:
47
Step-by-step explanation:
you should add 15 to 52 and then subtract 20 from 67 which you got from 52 plus 15
I think it might be commutative or associative but double check
Answer: (0,3) (1.5,0)
Step-by-step explanation: