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Bond [772]
3 years ago
8

Which model is most appropriate for the data shown in the graph below?

Mathematics
2 answers:
Ket [755]3 years ago
6 0

Answer : Exponential

The graph is attached below with dots

When we connect all the dots then we will get a curve shaped graph.

a). quadratic - A U shaped figure is quadratic. It is in the form of parabola.

b). linear - Line graph is linear. It is a straight line.

c). exponential - A curve shaped graph is exponential. Like half of a parabola.

d). line - Straight line graph.

By connecting all the dots we got a curve shaped graph. so its exponential.


iragen [17]3 years ago
3 0
It's most probably a C) exponential

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27^x = 9^x − 4 Question 1 options: x = 8 x = 4 x = −4 x = −8
Mariulka [41]

Answer:

x = -8

Step-by-step explanation:

Given the equation:

27^x=9^{x-4}

Note that

27=3^3\\ \\9=3^2,

then

27^x=(3^3)^x=3^{3x}\\ \\9^{x-4}=(3^2)^{x-4}=3^{2(x-4)}

Rewrite the equation as

3^{3x}=3^{2(x-4)},

then

3x=2(x-4)\\ \\3x=2x-8\\ \\3x-2x=-8\\ \\x=-8

4 0
3 years ago
The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

6 0
3 years ago
What are the dimensions of the container holding a 1" x 1" x 1" cube
Allushta [10]
Each dimension has to be 1" or bigger, otherwise the cube won't fit. _________ WAIT ! The container doesn't have to be rectangular, and that opens up a lot more possibilities. The smallest possible rectangular container is a little tiny cardboard cube whose dimensions are all 1", just like the contents. But you could also keep it in a container shaped like a pyramid, a cylinder, an egg, etc. If the container is a sphere, then its radius has to be at least 0.866 inch.
8 0
3 years ago
Coach Beard has 24 softballs to use this fall. She orders 2 more buckets of softballs that have 20 in each bucket. How many soft
jek_recluse [69]

Answer:

64 softballs

Step-by-step explanation:

Coach Beard currently already has 24 softballs.

When she orders 2 more buckets with 20 in each, that's another 20 + 20 = 40 softballs added to the original 24. So, let's add these two numbers:

24 + 40 = 64

The answer is 64 softballs.

<em>~ an aesthetics lover</em>

3 0
3 years ago
Read 2 more answers
Among all rectangles that have a perimeter of 182, find the dimensions of the one whose area is largest.
Evgen [1.6K]

Answer:

<em>The largest rectangle of perimeter 182 is a square of side 45.5</em>

Step-by-step explanation:

<u>Maximization Using Derivatives</u>

The procedure consists in finding an appropriate function that depends on only one variable. Then, the first derivative of the function will be found, equated to 0 and find the maximum or minimum values.

Suppose we have a rectangle of dimensions x and y. The area of that rectangle is:

A=x.y

And the perimeter is

P=2x+2y

We know the perimeter is 182, thus

2x+2y=182

Simplifying

x+y=91

Solving for y

y=91-x

The area is

A=x.(91-x)=91x-x^2

Taking the derivative:

A'=91-2x

Equating to 0

91-2x=0

Solving

x=91/2=45.5

Finding y

y=91-x=45.5

The largest rectangle of perimeter 182 is a square of side 45.5

6 0
3 years ago
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