Answer:
The horizontal distance from the plane to SCCA is 
Step-by-step explanation:
Let
x-----> the horizontal distance from the plane to SCCA
we know that
see the attached figure to better understand the problem
Answer:
a. y^2 = 8x.
Step-by-step explanation:
The general equation for this type of parabola is y^2 = 4ax where a is the distance between the vertex and the focus. The focal width = 4a.
So the answer to this is y^2 = 8x.
The trick here is to relate the NUMBER of coins to each other in one equation, and then the VALUE of the coins in another equation. If I have 1 dime, that 1 dime is worth 10 cents. The number of dimes is obviously not equal to the value. Let's call quarters q and dimes d. The number of these 2 types of coins added together is 80 coins. So q + d = 80. Now, we know that quarters are worth .25 and dimes are worth .1, so we express a quarter's worth as .25q; we express a dime's worth as .1d. The value of the coins we have is 14.90. So that equation is .25q + .1d = 14.90. Let's solve the first equation for q. q = 80 - d. We can now use that as a substitution for q into the second equation, giving us an equation with only 1 unknown, d. .25(80-d) + .1d = 14.90. Distributing through the parenthesis we have 20 - .25d + .1d = 14.90. Combining like terms gives us - .15d = - 5.1. We will divide both sides by - .15 to get that the number of dimes is 34. If we had a total of 80 coins, then the number of quarters is 80 - 34, which is 46. 46 quarters and 34 dimes
Answer:
21 adults and 139 children
Step-by-step explanation:
x=adult (8$)
y=child (5$)
8x + 5y =863
x+y=160
-x -x (subtract x on both sides)
y= -x + 160
plug that in for y on the other equation
8x + 5(-x + 160) =863
distribute 5 to both
8x + -5x + 800 = 863
combine both x values
3x + 800 = 863
-800 -800 (subtract on both sides)
3x = 63
divide by 3 on both sides
x = 21 adults
now plug x in one of the equations
21 + y = 160
-21 -21
y=139 children
