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Ksenya-84 [330]
3 years ago
14

Identify the minimum value of the function y = 2x2 + 4x Answer

Mathematics
2 answers:
iren2701 [21]3 years ago
4 0

Answer:

(-1, -2)

Step-by-step explanation:

Find the <em>x</em>-value the minimum occurs at. Use this value to find the minimum value. (Graph to find the highest point)

11111nata11111 [884]3 years ago
4 0

Answer:

y = - 2 is the minimum value

Step-by-step explanation:

The minimum value is the y- coordinate of the vertex.

The vertex lies on the axis of symmetry which is positioned at the midpoint of the zeros.

To find the zeros let y = 0, that is

2x² + 4x = 0 ← factor out 2x on the left side

2x(x + 2) = 0

Equate each factor to zero and solve for x

2x = 0 ⇒ x = 0

x + 2 = 0 ⇒ x = - 2

midpoint = \frac{0-2}{2} = - 1 ← x- coordinate of vertex

Substitute x = - 1 into the equation for corresponding y- coordinate

y = 2(- 1)² + 4(- 1) = 2 - 4 = -2

vertex = (- 1, - 2)

Hence minimum value = - 2

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PLEASE ANSWER THIS I BEG FOR YOUR MERCY!!!!!!!!!!!! if you dont know....dont answer
Andreyy89

Answer:

the answer is the second choice

Step-by-step explanation:

hopefully this helps :)

8 0
3 years ago
Times for an ambulance to respond to a medical emergency in a certain town are normally distributed with a mean of 450 seconds a
Gnoma [55]

Answer:

(D)109

Step-by-step explanation:

Mean = 450 seconds

Standard deviation = 50

First, we determine the probability that the expected response time is between 400 seconds and 500 seconds, P(400<x<500)

Using the Z-Score,

P(\frac{x-\mu}{\sigma}

From the Z-Score table

P(-1<x<1) = 0.68269  

The probability that the expected response time is between 400 seconds and 500 seconds is 0.68269.

Since there are 160 Emergencies

Number whose expected time is between 400 seconds and 500 seconds

=160 X 0.68269 \approx 109

6 0
3 years ago
Literally someone, please, anyone, help. i give the rest of my points
e-lub [12.9K]

Answer:

a). 3M = [ 6.5      1.3      23.4 ]

             [ 8.6      28.6   11.7   ]

b). 2M = [ 10        20        36  ]

             [ 24        44        18   ]

The number of each type of toy needed to be double the output.

( It looks like this is connected, if you need help, you can ask me, I have the whole PDF. And please give me Brainly for this =) Thank you. )

5 0
3 years ago
The NCAA is interested in estimating the difference in mean number of daily training hours for men and women athletes on college
hammer [34]

Answer:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data given

\bar X_M = 2.7 represent the sample mean for men

\bar X_F = 2.4 represent the sample mean for women

s_M = 0.3 represent the sample deviation for men

s_F = 0.4 represent the sample deviation for women

n_M = 10 sample size of male

n_F =10 sample size of women

The confidence interval is given by:

(\bar X_M -\bar X_F) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_M}+\frac{1}{n_F}}   (1)

The polled variance can be calculated with this formula:

s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125

s_p =\sqrt{0.125}=0.354

For a confidence of 95% the value for the significance is \alpha=1-0.95=0.05 and \alpha/2 = 0.025, the degrees of freedom are given by:

df = n_M + n_F -2= 10+10-2=18

And the critical value can be calculated with the following formula in excel: "=T.INV(1-0.025,18)" and we got t_{\alpha/2}=2.1

Now we can replace into the confidence interval:

(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032  

(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632  

6 0
3 years ago
What is the value of r (3,4), (-1,r),m=-3/4
Llana [10]

To find the value of r

We will follow the steps below

Usinf the equation of a slope:

slope(m) =

m=\frac{y_2-y_1}{x_2-x_1}

from the question given;

m= -3/4

x₁ = 3

y₁=4

x₂=-1

y₂=r

substituting the values into the slope formula

\frac{-3}{4}\text{ = }\frac{r-4}{-1-3}

we can now simplify and then solve for r

\frac{-3}{4}\text{ = }\frac{r-4}{-4}

cross-multiply

-3 x -4 = 4(r-4)

12 = 4(r-4)

Divide both-side of the equation by 4

\frac{12}{4}\text{ = }\frac{4(r-4)}{4}

3 = r - 4

add 4 to both-side of the equation

3+4 = r-4+4

7 = r

r=7

Therefore the value of r is 7

4 0
1 year ago
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