Answer: have you tried to use photomath?
Answer:
i)32C16
ii)1185408
<em><u>Explanation</u></em><em><u>:</u></em>
i)Total number of selected/eligible is 7+9+8+8=32
Total ways of selecting dance committee of 16 is
<em><u>3</u></em><em><u>2</u></em><em><u>C</u></em><em><u>1</u></em><em><u>6</u></em>
ii)Total ways of selecting 3 seniors from 8 is 8C3
and Total ways of selecting 6 juniors from 8 is 8C6
ways of selecting 2 sopho from 9 is 9C2
ways of selecting 5 freshman from 7 is 7C5
now, total way of selection come to be
8C3×8C6×9C2×7C5
=56×28×36×21
=1185408
✌️
Answer:
2/8 and 3/12
Step-by-step explanation:
You multiply both the numerator and denominator by the same number to get equivalent fractions.
1 x 2
4 x 2
= 2/8
and
1 x 3
4 x 3
= 3/12
Answer:
1.7689 (rounded to 4 decimal places)
Step-by-step explanation:
Let the number we are seeking be "x", thus we can write the equation as:
Since we have raised "x" to the "10th power", to get "x" back again, we need to take 10th root. Same goes for right side, we take 10th root of 300. We will get our answer. The process shown below:
![x^{10}=300\\\sqrt[10]{x^{10}} =\sqrt[10]{300} \\x=\sqrt[10]{300} \\x=1.7689](https://tex.z-dn.net/?f=x%5E%7B10%7D%3D300%5C%5C%5Csqrt%5B10%5D%7Bx%5E%7B10%7D%7D%20%3D%5Csqrt%5B10%5D%7B300%7D%20%5C%5Cx%3D%5Csqrt%5B10%5D%7B300%7D%20%5C%5Cx%3D1.7689)
hence, 1.7689 raised to 10th power will give us 300
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 152.5
For the alternative hypothesis,
µ ≠ 152.5
This is a two tailed test.
Since no population standard deviation is given, the distribution is a student's t.
Since n = 231
Degrees of freedom, df = n - 1 = 231 - 1 = 230
t = (x - µ)/(s/√n)
Where
x = sample mean = 148.9
µ = population mean = 152.5
s = samples standard deviation = 27.4
t = (148.9 - 152.5)/(27.4/√231) = - 2
We would determine the p value using the t test calculator. It becomes
p = 0.047
Since alpha, 0.05 > thanthere sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals the p value, 0.047, then we would reject the null hypothesis. Therefore, At a 5% level of significance, there is sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals
