f(x)=lnx
y=f(x)
dy/dx= 1/x
tangent at (x,y) has slope 1/x
eqn of tangent is y = mx + c
since the tangent passes through origin, c=0
substitute y = lnx and m= 1/x to above eqn
lnx = 1
x=e
y=lne=1
Answer:
DOC = 70
BOC = 110
AOD = 110
Step-by-step explanation:
AOB is supplementary to BOC and AOD, which means together they equal 180. 180-70=110, so BOC and AOD are both 110.
AOB and DOC are vertical angles to each other, so are AOD and BOC. Vertical angles are always equal to each other. So since AOB is 70, so is DOC.
Hope this makes sense:)
The equation for the table is f(x)=3x+1 so I don’t know for a but for b it would be f(x) because 1 is greater than 5.
Answer:
-3 degrees C
Step-by-step explanation:
We need to subtract 3 degrees from Thursdays temperature
0 - 3
-3 degrees C
Answer:
area of the larger figure=32 yd×37 yd
=1184 yd²
area of the smaller figure=21 yd ×26 yd
=546 yd²
area of the shaded region=1184 yd² -546 yd²
<em>=638 yd²</em>
