3,000.000 + 500.000 + 16.000 + 500 + 60 + 8 - Hope it helps!
The fewest number of days over which the tournament can take place is 5 days.
<h3>How to calculate the number of days?</h3>
As each team plays with other team Once and we have total 5 teams so number of matches will be (4+3+2+1)
Counted as team 1 plays with all other teams = 4 matches
Team 2 plays with team 3,4,5 =3 matches
Team 3 play with team 4,5=2 match
And the last match is between team 4 and team5
Total match = 10 and can be played two matches per day:
Number of days = 10/2
= 5 days.
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Answer:
-6.20x-6.20y=-948.6
add this to equation 2
6.20x-6.20x +9.30y-6.20y=1125.30-948.60
3.10y= 176.70
/3.10
y=176.70/3.10
y = 57 number of adult tickets
153-57=96 child tickets
Step-by-step explanation:
child admission is $6.20 : x numbers
adult admission is $9.30 : y numbers
153 tickets were sold
sales of $1125.30 .
x+y = 153.........................1
6.20x+9.30y= 1125.30..............2
Answer:
4th one its negative,linear association
Step-by-step explanation:
Answer:
Step-by-step explanation:
right triangle, so use the Pythagorean Theorem.
call the missing side c
17² + 8² = c²
353 = c²
c = √353 ≅ 18.8 in