Call the rate in still water vs;
upstream you have: vs-v=6/4
downstram you have: vs+v=6/3
where v is the rate with which the river flows.
rearranging:
vs-v=3/2
vs+v=2
from the second you have v=2-vs substitute into the first:
vs-2+vs=3/2
2vs=7/2
vs=7 mi/hr
516.66 <span>km
</span>
There are 100 m in 1 km
Therefore : 880 m = 0.88 km
435 km + 80.78 km + 0.88 km = 516.66 km
(4 meters) / (50 centimeters)
= (4 x 100 centimeters) / (50 centimeters)
= (400 centimeters) / (50 centimeters)
= (400) / (50)
= 8 .
We have been given that
Now, we need to find an ordered pair that must be on the graph of
On substituting x=0 in the above equation, we get
Therefore, the required ordered pair is given by (0,-1)
AB=48, DC=88
48+88=136
136÷2=68
Answer: LM=68
Remember that the length of the mid segment in a trapezoid is half the sum of the base lengths.
