Answer:
- see below for a drawing
- the area of one of the trapezoids is 20 units²
Step-by-step explanation:
No direction or other information about the desired parallelogram is given here, so we drew one arbitrarily. Likewise for the segment cutting it in half. It is convenient to have the bases of the trapezoids be the sides of the parallelogram that are 5 units apart.
The area of one trapezoid is ...
A = (1/2)(b1 +b2)h = (1/2)(3+5)·5 = 20 . . . . square units
The sum of the trapezoid base lengths is necessarily the length of the base of the parallelogram, so the area of the trapezoid is necessarily 1/2 the area of the parallelogram. (The area is necessarily half the area of the parallelogram also because the problem has us divide the parallelogram into two identical parts.)
Step-by-step explanation:
f(x) = 9 * 81^x
When x = -1/2,
f(-1/2) = 9 * 81^(-1/2) = 9 * (1/9) = 1.
346 divided by 2 would be 153. Subtract 92, and that would lead you with 61.
Therefore, the ultimate answer is 61.
The number of cats that you have is; 27 cats
<h3>How to calculate algebra word problems?</h3>
Let the number of cats alice has be x.
Since you have thrice the amount of cats that alice has, then you have 3x cats.
Bob has 7 less cats than you. Thus, bob has; 3x - 7
If they have a total of 56 cats, then;
x + 3x - 7 + 3x = 56
7x - 7 = 56
7x = 56 + 7
7x = 63
x = 63/7
x = 9
Thus, number of cats you have = 3x = 3 * 9 = 27 cats
Read more on algebra word problems at; brainly.com/question/13818690