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mafiozo [28]
1 year ago
8

Which equation represents the rectangular form of theta = 5Pi/6

Mathematics
1 answer:
Mrrafil [7]1 year ago
3 0

Answer:

D

Step-by-step explanation:

i just took a test with that question

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Alejandra can husk 8 ears of corn in 24 minutes. At this rate, how many ears of corn can she husk in 33 minutes?
8_murik_8 [283]
I'm afraid you're wrong. We may divide 24 by 8 to find out how long does it take for Alejandra to husk 1 ear of corn and then just divide 33 by the result:

24 ÷ 8 = 3

So Alejandra husks 1 ear of corn in 3 minutes.

33 ÷ 3 = 11

Answer: In 33 minutes Alejandra can husk <u>11 ears of corn</u>.
5 0
3 years ago
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What is the value of the exponent when simplifying the following expression: 16^1/2•16^1/2
pantera1 [17]

Answer:

B.

Step-by-step explanation:

because they have the same base and it's a multiplication so you have to add the exponents

6 0
2 years ago
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Sarah found that the product of 49 and 805 is 3,165. How would finding an estimate help her know that the answer is NOT reasonab
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Answer:

49 +805=3,165

Step-by-step explanation:

answer

she will have to count

6 0
3 years ago
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
2 years ago
Find the perimeter of the following shape: Shape ABCD is shown. Point A is at 7, 5. Point B is at 6, 3. Point C is at 3, 2. Poin
Art [367]
I think it A im not sure
8 0
3 years ago
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