1 is 25% of what number?

Evaluate square root of 16 minus x end root when x = 8.

My name is Ann [436]

$\sqrt{16-x}$
x=8
16-8=8
$\sqrt{8}$

Use a calculator to find the square root of 8.

7 0

3 years ago

Find the values of x and y.

gulaghasi [49]

Answer:

y=180-63-63/2=27degree...in triangle mln

x=180-27-63=90....in triangle mon

6 0

3 years ago

Read 2 more answers

The value of a car is $ 16,000 and depreciating at a rate of 11% per year. Write an

Mandarinka [93]

Answer- 16,000(0.88)t.

6 0

3 years ago

A manufacturer of detergent claims that the contents of boxes sold weigh on average at least 20 ounces. The distribution of weig

jenyasd209 [6]

Answer:

$z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625$

The p value for this case would be given by:

$p_v =P(z$

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

Step-by-step explanation:

Information provided

$\bar X=19.87$ represent the sample mean

$\sigma=0.4$ represent the population deviation

$n=25$ sample size

$\mu_o =68$ represent the value that we want to test

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is at least 20 ounces, the system of hypothesis would be:

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

The statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$z=\frac{19.87-20}{\frac{0.4}{\sqrt{25}}}=-1.625$

The p value for this case would be given by:

$p_v =P(z$

Since the p value is higher than the significance level provided we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 20 ounces.

7 0

3 years ago

Set up an equation and solve the following problem.

nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, t = $\dfrac{\textrm d miles}{\textrm s miph}$

Or, t = $\dfrac{\textrm 210 miles}{\textrm s miph}$

For Kent

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, T = $\dfrac{\textrm D miles}{\textrm S miph}$

Or, T = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

∵ Time taken by both is same

So, t = T

Or, $\dfrac{\textrm 210 miles}{\textrm s miph}$ = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴ s = $\dfrac{840}{20}$

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0

3 years ago