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Umnica [9.8K]
2 years ago
12

In a circle H with m angle GKJ=27 find the m angle GHJ

Mathematics
1 answer:
abruzzese [7]2 years ago
4 0

In a circle H with a measure of angle ∠GKJ = 27°. Then the measure of angle ∠GHJ will be 54°

<h3>What is a circle?</h3>

It is the center of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.

In a circle H with a measure of angle ∠GKJ = 27°.

Then the measure of angle ∠GHJ will be

We know that a chord's slope in the centre is double that of the chord's slope at the perimeter.

Then we have

∠GHJ = 2 x ∠GKJ

∠GHJ = 2 x 27°

∠GHJ = 54°

More about the circle link is given below.

brainly.com/question/11833983

#SPJ1

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In parallelogram DEFG, DH equals X +3, HF equals 3Y, GH equals 2X -5 and HE equals 5Y plus to find the values of X and Y
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<h3>How to determine the values of X and Y?</h3>

The figure that represents the complete question is added as an attachment

The given parameters are:

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From the attached parallelogram, we have:

DH = HF

GH = HE

Substitute the known values in the above equation

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