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Nadusha1986 [10]
3 years ago
12

Solve the formula for the indicated variable. A = 4πr² for r when r > 0 r =

Mathematics
2 answers:
SashulF [63]3 years ago
8 0

Answer:

√(A/4π) = r

Step-by-step explanation:

A = 4πr²

r² = A/4π

r = √(A/4π)

77julia77 [94]3 years ago
4 0

Answer:

r = \sqrt{\frac{A}{4\pi } }

Step-by-step explanation:

Given

A = 4πr² ( isolate r² by dividing both sides by 4π )

r² = \frac{A}{4\pi }

Take the square root of both sides

r = \sqrt{\frac{A}{4\pi } }

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tiny-mole [99]

Answer:

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Step-by-step explanation:

Surface area → area of 2 bases + area of 6 rectangles

Area of base is given

Area of rectangle → length × width

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3 years ago
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Jane is 5 times older than her sister. In 3 years, Jane’s sister will be 1/4 her age. Find the ages now
Korolek [52]

The present age of Jane is 45 years old and present age of her sister is 9 years old

<em><u>Solution:</u></em>

Let the present age of Jane be "x"

Let the present age of her sister be "y"

<em><u>Jane is 5 times older than her sister</u></em>

present age of Jane = 5(present age of her sister)

x = 5y ---------- eqn 1

<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>

Age of sister after 3 years = 3 + y

Age of jane after 3 years = 3 + x

Age of sister after 3 years = 1/4(age of jane after 3 years)

3 + y = \frac{1}{4}(3 + x)

Substitute eqn 1 in above equation

3 + y = \frac{1}{4}(3 + 5y)\\\\12 + 4y = 3 + 5y\\\\5y - 4y = 12 - 3\\\\y = 9

Substitute y = 9 in eqn 1

x = 5(9)

x = 45

Thus present age of Jane is 45 years old and present age of her sister is 9 years old

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4 years ago
Ricardo weigh 2pounds
IrinaVladis [17]

Answer:

I think that you are missing parts of your question as it is just a statement

Step-by-step explanation:

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4 years ago
A telephone pole that is 12 ft. tall has fallen against a house. If the top of the telephone pole touches the house 10 ft. above
Ostrovityanka [42]

Answer:

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Step-by-step explanation:

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sin^-1(sin(measure of the angle))=sin^-1(10/12)

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3 years ago
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5a-{3b-{4a-(5b-6a-7b)}]
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5a-[3b-\{4a-(5b-6a-7b)\}]\\\\=5a-[3b-\{4a-(-6a-2b)\}]\\\\=5a-[3b-\{4a+6a+2b\}]\\\\=5a-[3b-\{10a+2b\}]\\\\=5a-[3b-10a-2b]\\\\=5a-[b-10a]\\\\=5a-b+10a\\\\\boxed{=15a-b}
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