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Nat2105 [25]
2 years ago
15

How is the graph of the parent function of y = RootIndex 3 StartRoot 0.5 x EndRoot transformed to produce the graph y = RootInde

x 3 StartRoot x EndRoot?
It is horizontally stretched by a factor of mc031-3.
It is vertically stretched by a factor of mc031
It is translated left by mc031-5unit.
It is translated right by mc031-6.unit.
Mathematics
1 answer:
tresset_1 [31]2 years ago
5 0

If any constant is added in the variable of the function. Then the function will shift towards left. Then the correct option is C.

<h3>What is a function?</h3>

A statement, principle, or policy that creates the link between two variables is known as a function. Functions are found all across mathematics and are required for the creation of complex relationships.

The functions are given below.

y = ∛(0.5 + x)

y = ∛x

If any constant is added in the variable of the function. Then the function will shift towards left.

Then the correct option is C.

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

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matrenka [14]
Simple interest,
FV=P(1+ni)
FV=future value=2500
P=present value, invested amount
n=number of years, =3
i=annual interest rate, =0.095
2500=P(1+3(0.095))
Solve for P.
8 0
4 years ago
Raul ate 7/8 of 1/2 a pizza. How much of the pizza did Raul eat?
3241004551 [841]

Answer:

<u>7</u>

16

Step-by-step explanation:

7/8× 1/2=

<u>7 × 1</u><u> </u>

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5 0
3 years ago
Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
4 years ago
PLEASE HELP ME WITH THIS!!!
I am Lyosha [343]

Answer:

all are showing that y is a function of x

7 0
3 years ago
Which is the graph of linear inequality 6x + 2y &gt; –10?
Alecsey [184]

Hope it helps :) and let me know if you want me to explain why

6 0
3 years ago
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