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2 years ago

What is the solution for x in the equation?

Mathematics

2 answers:

sladkih [1.3K]2 years ago

3 0

Answer: 2.5

Step-by-step explanation:

-2x + 14 + 10x = 34

8x + 14 = 34

8x = 34 - 14

8x = 20

x = 20/8

x = 5/2

x = 2.5

wariber [46]2 years ago

3 0

Combine the like terms first
14 +8x =34
Subtract 14 both sides
8x = 20
Divide both sides by 8
x = 20/8
Reduce
x= 5/2
x = 2 1/2 or 2.5

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4 algebra 1 questions if you know the answers please try to get me to understand

asambeis [7]

Distribute each term in one parenthesis to the other terms in the other parenthesis.

(x - 2) (2x + 3)

First, distribute x. When distributing, multiply

x(2x) = 2x²

x(3) = 3x

Next, distribute the other term, -2. Remember to change the signs.

-2(2x) = -4x

-2(3) = -6

-------------------------------------------------------------------------------------------------------------------

2x² + 3x - 4x - 6

Combine like terms

3x - 4x = -x

2x² - x - 6

-------------------------------------------------------------------------------------------------------------------

2x² - x - 6 is your answer

hope this helps

3 0

3 years ago

Read 2 more answers

Which functions have graphs that are steeper than the graph of f(x)=−3x^2?

netineya [11]

Answer:

g(x)=−4x^2 and m(x)=4x^2

Step-by-step explanation:

A horizontal stretch or shrink happens when you multiply the parent function (in this case f(x) = x²) by a number. If this number is between 0 and 1, the graph will be stretched horizontally. If this number is greater than 1, the graph will be shrunk horizontally. If the number is between -1 and 0, the graph will be stretched horizontally and flipped; if the number is less than -1, the graph will be shrunk horizontally and flipped.

The graphs that are horizontally shrunk are steeper than the others. This is m(x)=4x^2 and g(x) = -4x^2.

8 0

3 years ago

Factor completely x^8- 16.

Nataly_w [17]

Answer:

Step-by-step explanation:

So in this example we'll be using the difference of squares which essentially states that: $(a-b)(a+b)=a^2-b^2$ or another way to think of it would be: $a-b=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b})$ . So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:

$x^8-16 = (x^4-4)(x^4+4)$

Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:

$x^4-4 = (x^2-2)(x^2+2)$

So completely factored form is: $(x^2-2)(x^2+4)(x^4+4)$

I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because $x^2+4 = x^2-(-4)$ . and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: $x^4+4 = x^4 - (-4) = (x^2-\sqrt{-4})(x^2+\sqrt{-4}) = (x^2-2i)(x^2+2i)$ just something that might be useful in some cases.