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leonid [27]
2 years ago
15

What is the solution for x in the equation?

Mathematics
2 answers:
sladkih [1.3K]2 years ago
3 0

Answer: 2.5

Step-by-step explanation:

-2x + 14 + 10x = 34

8x + 14 = 34

8x = 34 - 14

8x = 20

x = 20/8

x = 5/2

x = 2.5

wariber [46]2 years ago
3 0
Combine the like terms first
14 +8x =34
Subtract 14 both sides
8x = 20
Divide both sides by 8
x = 20/8
Reduce
x= 5/2
x = 2 1/2 or 2.5
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A line includes the points (-39,49) and (0,0). What is its equation in slope-intercept form?
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Answer:

The equation in the slope-intercept form will be:

y=-\frac{49}{39}x+0

Step-by-step explanation:

Given the points

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Finding the slope between the points using the formula

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-39,\:49\right),\:\left(x_2,\:y_2\right)=\left(0,\:0\right)

m=\frac{0-49}{0-\left(-39\right)}

m=-\frac{49}{39}

We know that the point-slope of the line equation is

y-y_1=m\left(x-x_1\right)

substituting m=-\frac{49}{39} and (-39,49)  in the equation

y-y_1=m\left(x-x_1\right)

y-49=\frac{-49}{39}\left(x-\left(-39\right)\right)

Now writing the equation in slope-intercept form

y=mx+b

where m is the slope and b is the y-intercept

y-49=\frac{-49}{39}\left(x-\left(-39\right)\right)

y-49=\frac{-49}{39}\left(x+39\right)

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

y-49=-\frac{49}{39}\left(x+39\right)

\mathrm{Add\:}49\mathrm{\:to\:both\:sides}

y-49+49=-\frac{49}{39}\left(x+39\right)+49

y=-\frac{49}{39}x+0              ∵ y=mx+b

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3 years ago
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kondaur [170]

<u>Answer: </u>

The solution of \bold{\frac{M^{2}}{P^{2}}} for M = 10, N = -5P and P = -2  is 25

<u>Solution: </u>

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of \frac{M^{2}}{P^{2}},  

By substituting the values of M and N, we get

\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}

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Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.  

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