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Ymorist [56]
2 years ago
7

Convert 675 to octal​

Mathematics
1 answer:
Sonbull [250]2 years ago
3 0

Step-by-step explanation:

step 1 = Divide 675 by 8 keeping notice of the quotient and the remainder.

step 2 =Continue dividing the quotient by 8 until you get a quotient of zero.

step 3 = Then just write out the remainders in the reverse order to get octal equivalent of decimal number 675.

Using the above steps, here is the work involved in the solution for converting 675 to octal number:

675 / 8 = 84 with remainder 3

84 / 8 = 10 with remainder 4

10 / 8 = 1 with remainder 2

1 / 8 = 0 with remainder 1

Then just write down the remainders in the reverse order to get the answer, The decimal number 675 converted to octal is therefore equal to :

1243

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Jeanne has $14800, 3 and half loan with a high APR of 8.57 due to her less-than-average credit rating. What is the monthly payme
snow_lady [41]

Jeanne has $14800, 3 and half year loan with a high APR of 8.57 due to her less-than-average credit rating. What is the monthly payment for this loan?

Answer:

$409.57

Step-by-step explanation:

The formula for loan payment is given by:

p= \frac{r(pv)}{1-(1+r)^{-n} }

pv = present value

r = rate per period

n = number of periods

Loan period is  3 and half years

for monthly payments, number of periods is (3 and half years) x 12 months

= 3.5 x 12 months = 42 months

Annual Payment Rate = 8.57 percent = 8.57/100 =0.0857

Rate per month = Annual Payment Rate /12 months  

=  0.0857/ 12 = 0.00714

P = \frac{0.00714(14800)}{1-(1+0.00714)^{-42} }

\frac{105.67}{1-(1.00714)^{-42} }

\frac{105.67}{1-0.742} }

= \frac{105.67}{0.258 }= $409.57

3 0
3 years ago
Nita finds that the expression (a + 1) 2 is sometimes, but
kenny6666 [7]

I guess the expressions are supposed to be (<em>a</em> + 1)² and (<em>a</em> + 1)³.

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(<em>a</em> + 1)² > (<em>a</em> + 1)³

Move everything to one side:

(<em>a</em> + 1)² - (<em>a</em> + 1)³ > 0

Factorize the left side:

(<em>a</em> + 1)² (1 - (<em>a</em> + 1)) > 0

-<em>a</em> (<em>a</em> + 1)² > 0

<em>a</em> (<em>a</em> + 1)² < 0

Notice that the left side is exactly 0 if either <em>a</em> = 0 or <em>a</em> = -1.

Now consider the following 3 cases:

• If <em>a</em> < -1, then <em>a</em> is negative, while (<em>a</em> + 1)² is always non-negative, which means <em>a</em> (<em>a</em> + 1)² will always be negative.

• If -1 < <em>a</em> < 0, then again <em>a</em> is negative, so <em>a</em> (<em>a</em> + 1)² is also negative.

• If <em>a</em> > 0, then <em>a</em> (<em>a</em> + 1)² is always positive.

So the inequality is satisfied for all <em>a</em> in the interval (-∞, -1) ∪ (-1, 0). This is to say that (<em>a</em> + 1)² is always greater than (<em>a</em> + 1)³ if <em>a</em> is chosen from this domain.

Another way to look at this: assume <em>a</em> + 1 falls between -1 and 1. Whenever you scale a number between -1 and 1 by another number in the same range, the product will always be smaller than the original number.

More concretely, let's say <em>a</em> + 1 = 1/2. So for instance, 1/2 * 1/2 = (1/2)² = 1/4, and 1/4 is clearly smaller than 1/2. If we multipy again by 1/2, we get 1/2 * 1/2 * 1/2 = (1/2)³ = 1/8, which is smaller than 1/4.

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