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kogti [31]
2 years ago
13

An ice cream store sells 27 flavors of ice cream. Determine the number of 6 dip sundaes. How many 6 dip sundaes are possible if

order is not considered and no flavor is​ repeated?
Mathematics
1 answer:
Bond [772]2 years ago
6 0

There are 2.4286782`9969 \times 10^{15} of 6 dip sundaes that are possible if the order is not considered and no flavour is​ repeated.

Given that, an ice cream store sells 27 flavours of ice cream.

We need to find how many 6 dip sundaes are possible if the order is not considered and no flavour is​ repeated.

<h3>What are combinations?</h3>

In mathematics, a combination is a selection of items from a set that has distinct members, such that the order of selection does not matter.

This problem deals with combinations, whose formula is C(m, n)=\frac{m!}{n!.(m-n)!}.

For 27 flavours of ice cream and 6 dip sundaes, m = 27 and n = 6.

Now, C(27, 6)=\frac{27!}{6!.(27-6)!}=\frac{27!}{6!.13!} =2.4286782`9969 \times 10^{15}

Hence, there are 2.4286782`9969 \times 10^{15} of 6 dip sundaes that are possible if the order is not considered and no flavour is​ repeated.

To learn more about combinations visit:

brainly.com/question/19692242.

#SPJ1

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