we know that
the rate of a linear equation is equal to the slope
Step 1
Find the bear’s average heart rate when it’s active
Let
A(1.5,90) B ( 2,120)
the slope is equal to
m=(y2-y1)/(x2-x1)
m=(120-90)/(2-1.5)=30/0.5
m=60 heartbeats/min
therefore
the answer part a) is
the bear’s average heart rate when it’s active is 60 heartbeats/min
Step 2
Find the bear’s average heart rate when it’s hibernating
Let
A(1.5,18) B ( 2,24)
the slope is equal to
m=(y2-y1)/(x2-x1)
m=(24-18)/(2-1.5)=6/0.5
m=12 heartbeats/min
therefore
the answer part b) is
the bear’s average heart rate when it’s hibernating is 12 heartbeats/min
Answer:Yes it does
Step-by-step explanation:because it goes on the right path
Answer:
A. 3
Step-by-step explanation:
In a function, the inputs do not repeat.
The inputs are assigned to exactly one output for each.
Three is one of the options. Three is already an input in the given function.
Replacing the ? with 3 would create the non-function.
(3,5) (2, 4) (9, 0) (3,6)
Option A should be the correct answer.
Hope this helps.
So for this problem, you will need to write out the equation before you can solve the question. The square of two times an integer translates into 2x². In a word problem, "is" means =. Therefore, 2x² is equal to the other half of the equation. To write out the other half of the equation, you have to know that "is more than" means addition. So, 10x+6 is the other half of the equation. your final equation becomes 2x²=10x+6. Then solve the equation like in any other problem: 2x²=10x+6 becomes 2x²-10x-6=0, and then factor or use the quadratic formula.
so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well, you know, if we end up with a 0 at the denominator, like
then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.
so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".
