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Zielflug [23.3K]
3 years ago
11

The square of two times an interger is 6 more than ten times the integer. Find the integer

Mathematics
1 answer:
MArishka [77]3 years ago
3 0
So for this problem, you will need to write out the equation before you can solve the question. The square of two times an integer translates into 2x². In a word problem, "is" means =. Therefore, 2x² is equal to the other half of the equation. To write out the other half of the equation, you have to know that "is more than" means addition. So, 10x+6 is the other half of the equation. your final equation becomes 2x²=10x+6. Then solve the equation like in any other problem: 2x²=10x+6 becomes 2x²-10x-6=0, and then factor or use the quadratic formula.
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What is the probability that 2 randomly selected months have 31 days?
aniked [119]

Answer:

31.8%

Step-by-step explanation:There are 7 months that have 31 days so,

The odds the first selected month has 31 days is 7/12

The next month there are only 6 months left with 31 days of only 11 months to choose from

so the odds for the second are 6/11

To calculate the odds they BOTH  have 31 months you multiply the two odds:

(7/12) x (6/11) = 42/132 = .318 so 31.8%

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3 years ago
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What is a correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9?
Sholpan [36]

Answer:

the first step is to distribute the -4 to (3-5x)

Step-by-step explanation:

3 0
3 years ago
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Two boats leave the same place at the same time. The first boat heads due north at 10 kilometers per hour. The second boat heads
Maksim231197 [3]

Answer:

18.87 km/hr

Step-by-step explanation:

First boat is heading North with a speed of 10 km/hr.

Second boat is heading West with a speed of 16 km/hr.

Time for which they move = 2.5 hours

To find:

The speed at which the distance is increasing between the two boats.

Solution:

Let the situation be represented by the attached diagram.

Their initial position is represented by point O from where they move towards point A and point B respectively.

Distance = Speed \times Time

Distance\ OA = 10 \times 2.5 = 25\ km

Distance\ OB = 16 \times 2.5 = 40\ km

We can use Pythagorean Theorem to find the distance AB.

AB is the hypotenuse of the right angled \triangle AOB.

According to Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^2 = 25^2 + 40^2\\\Rightarrow AB^2 = 2225^2\\\Rightarrow AB^2 \approx 47.17\ km

The speed at which distance is increasing between the two boats is given as:

\dfrac{47.17}{2.5} \approx 18.87\ km/hr

4 0
2 years ago
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