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Zielflug [23.3K]
3 years ago
11

The square of two times an interger is 6 more than ten times the integer. Find the integer

Mathematics
1 answer:
MArishka [77]3 years ago
3 0
So for this problem, you will need to write out the equation before you can solve the question. The square of two times an integer translates into 2x². In a word problem, "is" means =. Therefore, 2x² is equal to the other half of the equation. To write out the other half of the equation, you have to know that "is more than" means addition. So, 10x+6 is the other half of the equation. your final equation becomes 2x²=10x+6. Then solve the equation like in any other problem: 2x²=10x+6 becomes 2x²-10x-6=0, and then factor or use the quadratic formula.
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Help please, this is annoying lol
horrorfan [7]

Answer:

<em>Cost</em>=x25+200

Step-by-step explanation:

The amount of people is unknown but each person the cost will be $25 for refreshments per each passenger; the limo cost $200 once you figure out how many people will go to prom x will be, EXAMPLE: x=6 times $25 plus $200 which will give you the cost.

5 0
3 years ago
PLEASE HELPPPPP MATH
Stels [109]

Answer:

Use the equation 250+25w=400+20w

Step-by-step explanation:

Replace w with one of the answers until you get the right one.

pretty sure its 35 but I don't have a calculator with me so double check

6 0
3 years ago
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Please help me asap.
Makovka662 [10]

The first one is the answer you're looking for

6 0
3 years ago
Let a and b be positive integers. 23^a x 23^b
Ket [755]

Answer:

23 ^ ( a+b)

Step-by-step explanation:

23^a *23^b

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23 ^ ( a+b)

6 0
3 years ago
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a geometric series where the first term is -12, the last term is -972, and each term after the first is triple the previous term
Luba_88 [7]

Answer:

the geometric series is a(n) = -12(3)^(n-1)

Step-by-step explanation:

"Triple" denotes multiplication by 3.  Thus, the common factor here is 3.

The general formula for a geometric series is a(n) = a(1)(r)^(n-1), where a(1) is the first term, r is the common ratio.

Here, we have a(n)= (-12)(3)^(n-1) = -972.

We need to solve this for n, which represents the last term.

The first step towards solving for n is to divide both sides by -12:

3^(n-1) = 81

To solve for n-1, rewrite 81 as 3^4.  Then we have:

3^(n-1) = 3^4, implying that (n-1) = 4 and that n = 5.

Then we know that it is the 5th term that equals -972.

In summary, the geometric series is a(n) = -12(3)^(n-1).

8 0
3 years ago
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