An expression that is equivalent to the statement Subtract a from the quotient of 6 and B is 6/b - a
<h3>How to write equivalent expression</h3>
Given statement
Subtract a from the quotient of 6 and B
- The quotient of 6 and B can be written as 6/B
- a subtracted from 6/B is written as
6/B - a
Therefore, the correct option equivalent to the statement is option A) 6/B - a
Learn more about equivalent expression:
brainly.com/question/2972832
let's firstly convert the mixed fractions to improper fractions and then divide.
![\bf \stackrel{mixed}{17\frac{13}{18}}\implies \cfrac{17\cdot 18 +13}{18}\implies \stackrel{improper}{\cfrac{319}{18}}~\hfill \stackrel{mixed}{2\frac{7}{9}}\implies \cfrac{2\cdot 9+7}{9}\implies \stackrel{improper}{\cfrac{25}{9}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B17%5Cfrac%7B13%7D%7B18%7D%7D%5Cimplies%20%5Ccfrac%7B17%5Ccdot%2018%20%2B13%7D%7B18%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B319%7D%7B18%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B7%7D%7B9%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%209%2B7%7D%7B9%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B25%7D%7B9%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \cfrac{319}{18}\div \cfrac{25}{9}\implies \cfrac{319}{\underset{2}{~~\begin{matrix} 18 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{\stackrel{1}{~~\begin{matrix} 9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{25}\implies \cfrac{319}{50}\implies 6\frac{19}{50}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B319%7D%7B18%7D%5Cdiv%20%5Ccfrac%7B25%7D%7B9%7D%5Cimplies%20%5Ccfrac%7B319%7D%7B%5Cunderset%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%2018%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%5Ccdot%20%5Ccfrac%7B%5Cstackrel%7B1%7D%7B~~%5Cbegin%7Bmatrix%7D%209%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%7B25%7D%5Cimplies%20%5Ccfrac%7B319%7D%7B50%7D%5Cimplies%206%5Cfrac%7B19%7D%7B50%7D)
Answer:
a. 9.5x + 6.5(x+c) < 8 when c>0
b. Must be one child more than the no. of adults.
Step-by-step explanation:
For Cinema 1:
for adult = $9.50
for child = $6.50
For Cinema 2:
Per person regardless of age = $8.00
First of all, we will find out the condition when per person rates in both cinema are equal.
Assume x = no. of adults
y = no. of children
Rate per person in Cinema I = Rate per person in Cinema II
(9.5x + 6.5y)/(x+y) = 8
9.5x + 6.5y = 8(x+y)
9.5x + 6.5y = 8x + 8y
9.5x-8x = 8y-6.5y
=> x = y
So rates are equal when no. of adults equals no. of children
For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8
Hence we form an inequality when y = x+c and c > 0
9.5x + 6.5(x+c) < 8 when c>0
Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.
Answer:
ANSWER
y = 3x + 6.50
EXPLANATION
The $3 for each downloaded movie is the unit rate of change.
This is represent the slope of the linear function that models this situation.
The monthly fee of monthly fee of $6.50 the constant rate.
It represents the y-intercept of the function.
The linear function is given by
y = mx + by=mx+b
The correct choice is y = 3x + 6.50
Answer:
6^10 over 7^6.
Step-by-step explanation:
(6^5 over 7^3)^2
= 6^(5*2) / 7^(3*2)
= 6^10 over 7^6.
