Isosceles right triangle is a 90 45 45 degree triangle
leg = 12.6 / sq rt(2)
leg = 12.6 /
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1.4142135624
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leg =
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8.909545443
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Answer:
x = 6
Step-by-step explanation:

We can multiply both sides by 1.5 to isolate x

JK + KL = JL
JK = 2x, KL = x + 2, JL = 5x - 10
therefore we heve the equation:
2x + (x + 2) = 5x - 10
3x + 2 = 5x - 10 |-2
3x = 5x - 12 |-5x
-2x = -12 |:(-2)
x = 6
JK = 2x → JK = 2(6) = 12
KL = x + 2 → KL = 6 + 2 = 8
JL = 5x - 10 → JL = 5(6) - 10 = 30 - 10 = 20
Check:
JK + KL = JL
12 + 8 = 20 CORRECT :)
Answer:
the rate of change is 5
Step-by-step explanation:
$90 / 18 cars = $5 per car
$45 / 9 cars = $5 per car
$60 / 12 cars = $5 per car
That means the rate of change is 5 (5/1)
Let's assume
It started in 2000
so, t=0 in 2000

we can use formula

we can plug value

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million
so, at t=2005-2000=5
P(t)=7.3 million
we can plug value and then we can solve for r


now, we can plug back

now, we have
P(t)=1 billion =1000 million
so, we can set it and then we can solve for t


approximately

Year is 2000+192
year is 2192................Answer