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astraxan [27]
3 years ago
13

you have housing and fixed expenses of $631.72/month and they are 33% of your realized income. What is our realized income per m

onth?
Mathematics
2 answers:
Elza [17]3 years ago
7 0

Answer:

Our realized income per month = $1914.30

Step-by-step explanation:

Amount of housing and fixed expenses per month = $631.72

Also, given that the housing and fixed expenses per month are 33% of your realized income

We need to find the realized income per month

Let the realized income per month be $x

⇒ 33% of realized income = Fixed expenses

⇒ 0.33 × x = 631.72

⇒ x = 1914.30

Therefore, Our realized income per month = $1914.30

nikklg [1K]3 years ago
6 0
631.72 = 33% of Realized Income 
<span>631.72 / .33 = Realized Income </span>
<span>1914.30 = Realized Income</span>
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Find the area and the perimeter of the shaded region
lyudmila [28]

Answer:

area: 41.04 cm² ; perimeter 35.8 cm

Step-by-step explanation:

Perimeter of shaded area = 1/4 perimeter of circle + line AC = ¼ * 3.14 * 2 * 12 + √(12² + 12²) = 18.84 + 12√2 cm = 35.8 cm

Area of Shaded Region = 1/4 area of circle - area of triangle = ¼ * 3.14 * 12² - ½ . 12 * 12

= (¼ * 3.14 - ½) * 12² = 41.04 cm²

8 0
3 years ago
Find the sum of the first 20 terms of the arithmetic sequence 4, 10, 16, 22....
hammer [34]

n = 20

d = 6

a = 4

L = a + (n - 1)*d

L = 4 + (20 - 1)*6

L = 4 + 19*6

L = 118

Sum = (a + L)*n/2

Sum = (4 + 118) * 20/2

Sum = 122 * 10

Sum = 1220

3 0
4 years ago
Suppose the lifetime of a cell phone battery is normally distributed with a mean of 36 months and a standard deviation of 2 mont
solong [7]

Answer:

They should guarantee the lifetime of their batteries for 32 months.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 36 months and a standard deviation of 2 months.

This means that \mu = 36, \sigma = 2

If the company wants to replace no more than 2% of all batteries, for how many months should they guarantee the lifetime of their batteries?

The guarantee should be the 2th percentile of lengths, which is X when Z has a pvalue of 0.02. So X when Z = -2.054.

Z = \frac{X - \mu}{\sigma}

-2.054 = \frac{X - 36}{2}

X - 36 = -2.054*2

X = 31.89

Rounding to the closest month, 32.

They should guarantee the lifetime of their batteries for 32 months.

3 0
3 years ago
Solve the equation for y<br> y +5=-(x – 3)
goldenfox [79]

Answer:

y=-x-2

Step-by-step explanation:

y+5=-(x-3)

y+5=-x+3

y=-x+3-5

y=-x-2

6 0
3 years ago
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The answer would be $6.40
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4 years ago
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