For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
3x - 8 = -2 |subtract 10 from both sides
3x - 18 = -12 |divide both sides by 3
x - 6 = -4
The answer i c,because if u sum it up,u get that
Hello there! We can solve this question by writing and solving a proportion. Set it up like this:
9/x = 3/100.
This is because 9 is 3% of x number of stores and percents are parts of 100. Setting it up like this will help us get the correct answer. Cross multiply the values . 9 * 100 is 900 and 3 * x = 3x. You get 900 = 3x. Now, divide each side by 3 to isolate the x. 3x/3 cancels out the x. 900/3 is 300. There. x = 300. 9 stores is 3% of 300 stores.
