It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.
The simplest polynomial with these characteristics would be

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

Answer:
There is no change.
Step-by-step explanation:
For example, if we use 5+3=8.
If you change it to 3+5, it still equals 8.
Therefore, 3+5=5+3 because at the end, they both have equal value aka both end up with 8 using the same numbers. (goes by the rule a+b=b+a)