High positive correlation<span>
</span>
What is your grade level and which curriculum are you using?
Using the normal distribution, it is found that 0.0329 = 3.29% of the population are considered to be potential leaders.
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 550, hence
.
- The standard deviation is of 125, hence
.
The proportion of the population considered to be potential leaders is <u>1 subtracted by the p-value of Z when X = 780</u>, hence:



has a p-value of 0.9671.
1 - 0.9671 = 0.0329
0.0329 = 3.29% of the population are considered to be potential leaders.
To learn more about the normal distribution, you can take a look at brainly.com/question/24663213
Answer:
A = 20°
AC = 6.6
BC = 2.4
Step-by-step explanation:
Given:
B = 70°
C = right angle = 90°
AB = 7
Required:
A, AC, and BC
Solution:
✔️A = 180 - (90 + 70) (sum of triangle)
A = 20°
✔️Use trigonometric function to find AC:
Refernce angle = 70°
Opp = AC
Hypotenuse = 7
Apply SOH,
sin 70 = Opp/Hyp
sin 70 = AC/7
7 * sin 70 = AC
6.57784835 = AC
AC = 6.6 (nearest tenth)
✔️Use trigonometric function to find Bc:
Refernce angle = 70°
Adj = BC
Hypotenuse = 7
Apply CAH,
cos 70 = Adj/Hyp
cos 70 = BC/7
7 * cos 70 = BC
2.394141 = BC
BC = 2.4 (nearest tenth)