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2 years ago

Using the Vertical Line Test Which graph does not represent a function?

Mathematics

1 answer:

Nadusha1986 [10]2 years ago

5 0

Using the Vertical Line Test, the graph does not represent a function is ellipse, the third graph.

<h3>What is vertical line test?</h3>

The vertical line test is a graphical method of determining whether a curve in the plane represents the graph of a function. It is done by visually examining the number of intersections of the curve with vertical lines.

Any vertical line in the x y plane must intersect the graph of a function at most once.

In the given graphs, the graph of a function intersects the y axis twice. So, it is not a function.

From the given graphs, the third graph which is of ellipse crosses the vertical line twice.

Thus, the graph does not represent a function is ellipse.

Learn more about vertical line test.

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cestrela7 [59]

Answer:

The answer is B. 41.4 feet.

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3 years ago

600% as a decimal and fraction or mixed number

OleMash [197]

Hello there!

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3 years ago

Read 2 more answers

The average rate of change of g(x) between x = 4 and x = 7 is 5/6 . Which statement must be true?

Blizzard [7]

Answer:

$\frac{5}{6}=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}$ would be the correct statement.

Step-by-step explanation:

As we know that

Average rate of change = Change in output / Change in input

= Δy / Δx

$=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}$

$=\frac{g(x_{2})-g(x_{1})}{x_{2}-x_{1}}$

$=\frac{g(7)-g(4)}{7-4}$

As the average rate of change of g(x) between x = 4 and x = 7 is 5/6.

$\:Average\:rate\:of\:change\:=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}$

$\frac{5}{6}=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}$

Therefore, $\frac{5}{6}=\:\frac{g\left(7\right)-g\left(4\right)}{7-4}$ would be the correct statement.

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3 years ago

A runner is participating in a 10.3 mile race. If the runner stopped at a water station that is twice as far from the starting l

Rudik [331]

We have the representation of this problem in the figure below. As we have a 10.3 mile race, then the equation is fulfilled as:

$d = 10.3mi = d_{1}+ d_{2}$

We know that there is <span>a water station that is twice as far from the starting line as from the finish line, then:

</span> $d_{2}=2d_{1}$

So:

$d_{1} +2d_{1}=10.3$
∴ $d_{1}=3.43mi$

and $d_{2}=2(3.43)=6.86mi$

<span>Finally, the distance of the runner from the finish line is:
</span>
$6.86mi$

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3 years ago

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Vaselesa [24]

-23/6,-2.18,√17,8 7/12,8.6,3√12

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