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2 years ago

a ________________ is the flat, low-lying area adjacent to a stream channel that receives overbank flow

Engineering

1 answer:

Umnica [9.8K]2 years ago

5 0

Answer:

flood plain

Explanation:

it should be called a flood plain which makes sense because it’s not a deposition.

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Some connecting rods have ____ to help lubricate the cylinder wall or piston pin.

Ket [755]

Answer:

some connecting rods have spit holes

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4 years ago

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A) For Well A, provide a cross-section sketch that shows (i) ground elevation, (ii) casing height, (iii) depth to

Ad libitum [116K]

Don’t go on that file will give a virus! Sorry just looking out and I don’t know how to comment!

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3 years ago

Water flows through a pipe of 100 mm at the rate of 0.9 m3 per minute at section A. It tapers to 50mm diameter at B, A being 1.5

pochemuha

Answer:

The velocities in points A and B are 1.9 and 7.63 m/s respectively. The Pressure at point B is 28 Kpa.

Explanation:

Assuming the fluid to be incompressible we can apply for the continuity equation for fluids:

$Aa.Va=Ab.Vb=Q$

Where A, V and Q are the areas, velocities and volume rate respectively. For section A and B the areas are:

$Aa=\frac{pi.Da^2}{4}= \frac{\pi.(0.1m)^2}{4}=7.85*10^{-3}\ m^3$

$Ab=\frac{pi.Db^2}{4}= \frac{\pi.(0.05m)^2}{4}=1.95*10^{-3}\ m^3$

Using the volume rate:

$Va=\frac{Q}{Aa}=\frac{0.9m^3}{7.85*10^{-3}\ m^3} = 1.9\ m/s$

$Vb = \frac{Q}{Ab}= \frac{0.9m^3}{1.96*10^{-3}\ m^3} = 7.63\ m/s$

Assuming no losses, the energy equation for fluids can be written as:

$Pa+\frac{1}{2}pa.Va^2+pa.g.za=Pb+\frac{1}{2}pb.Vb^2+pb.g.zb$

Here P, V, p, z and g represent the pressure, velocities, height and gravity acceleration. Considering the zero height level at point A and solving for Pb:

$Pb=Pa+\frac{1}{2}pa(Va^2-Vb^2)-pa.g.za$

Knowing the manometric pressure in point A of 70kPa, the height at point B of 1.5 meters, the density of water of 1000 kg/m^3 and the velocities calculated, the pressure at B results:

$Pb = 70000Pa+ \frac{1}{2}*1000\ \frac{kg}{m^3}*((1.9m/s)^2 - (7.63m/s)^2) - 1000\frac{kg}{m^3}*9,81\frac{m}{s^2}*1.5m$

$Pb = 70000\ Pa-27303\ Pa - 14715\ Pa$

$Pb = 27,996\ Pa = 28\ kPa$

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3 years ago

For a gearbox power and efficiency test apparatus that accommodates interchangeable gearboxes, drive up to 0.5kW. How to select

BigorU [14]

Answer:

First we must know the efficiency of the gearbox in which energy is lost by friction between its components, we divide this efficiency by the nominal power and find the real power.

With this value knowing the speed of rotation of the gearbox we select an engine that has a power just above.

Also keep in mind that the motor torque must be greater than the resistance offered by the gearbox and the 0.5Kw machine

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4 years ago

You are approaching an intersection on a multiple-lane road, and you want to change lanes;

Ipatiy [6.2K]

Answer:

The correct answer is B

Explanation:

On a multiple lane roadway that has a speed limit of 50 mph (that is 80.5kmh) or greater, a driver is legally required to signal his or her intention to change lanes at least 300 feet in advance of making the change.

This rule like other traffic rules is design to ensure the safety of other road users by preventing accidents which may stem from reckless driving.

Cheers!

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3 years ago

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