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aleksandrvk [35]
3 years ago
14

The gross weight of a two-place Piper Cherokee is 2000lb and its wing area is 160 ft^2. What is its wing loading

Engineering
1 answer:
Novay_Z [31]3 years ago
3 0

Answer:

W = 12.5\ lb/ft^2 --- in lb/ft^2

W = 598.503N/m^2 --- in N/m^2

Explanation:

Given

Weight=2000lb

Area = 160ft^2

Required

Determine the wing loading (W)

Wing loading is calculated using:

W = \frac{Weight}{Area}

Substitute values for Weight and Area

W = \frac{2000lb}{160ft^2}

W = 12.5\ lb/ft^2

The answer can also be converted to N/m^2

1\ lb = 4.4482216153N

1ft^2 = 0.092903m^2

So, we have:

W = \frac{12.5 * 4.4482216153N}{0.092903m^2}

W = \frac{55.6027701912N}{0.092903m^2}

W = 598.503N/m^2

Hence, the wing loading is:

W = 12.5\ lb/ft^2 --- in lb/ft^2

W = 598.503N/m^2 --- in N/m^2

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Noise or sound is the energy produced by sounding object which can be felt by our hearing organs .

Explanation:

Noise is produced by vibration in a body.

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3 years ago
What is the different between isometric view and isometric projection
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All the dimensions in the isometric drawing are actual while when in the Isometric projection due to this it has to be the isometric scale is to be used.

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2. What is the charge, expressed in micro coulombs on two equally and similarly charges spheres placed in air with their centres
9966 [12]

Answer:

q = 0.1086 micro Coulombs

Explanation:

By Coulombs law, we have;

F =k \times  \dfrac{ q_1 \times q_2}{r^2}

Where;

F = The electric force = 120 mgm

q₁ and q₂ = Charge

r = The separating distance = 30 cm = 0.3 m

k = 8.9876×10⁹ kg·m³/(s²·C²)

Where, q₁ and q₂, we have;

F =k \times  \dfrac{ q^2}{r^2}

Whereby the force is the force of 120 milligram mass, we have;

0.00012 × 9.81 = 000011772 N

q = \sqrt{ \dfrac{ F\times r^2}{k}}

Substituting the values, we have;

q = \sqrt{ \dfrac{ 000011772 \times (0.3)^2}{8.9876 \times 10^9}} = 1.086 \times 10 ^{-7} \ Coulombs

q = 0.1086 micro Coulombs.

5 0
3 years ago
An engine operates on gasoline (LHV=44 MJ/kg) with a brake thermal efficiency of 37.9 % What is the brake specific fuel consumpt
scZoUnD [109]

Answer:

s =0.21\ kg/Kw.hr

Explanation:

Given that

Calorific value (CV) = 44 MJ/Kg

CV= 44,000 KJ/kg

Brake thermal efficiency(η) = 37.9 %

We know that

\eta =\dfrac{BP}{\dot{m_f}\times CV}

Where BP is the brake power

\eta =\dfrac{BP}{\dot{m_f}\times CV}

0.379 =\dfrac{BP}{\dot{m_f}\times 44000}

\dfrac{BP}{\dot{m_f}}=16676

Brake specific fuel consumption (s)

s =\dfrac{\dot{m_f}}{BP}

s =\dfrac{3600\times \dot{m_f}}{BP}

s =\dfrac{3600}{16,676}\ kg/Kw.hr

s =0.21\ kg/Kw.hr

7 0
3 years ago
A non-inductive load takes a current of 15A at 125V. An inductor is then connected in series in order that the same current shal
Norma-Jean [14]

Answer:

The inductance of the inductor is 0.051H

Explanation:

From Ohm's law;

  V = IR .................. 1

The inductor has its internal resistance referred to as the inductive reactance, X_{L}, which is the resistance to the flow of current through the inductor.

From equation 1;

V = IX_{L}

X_{L} = \frac{V}{I} ................ 2

Given that; V = 240V, f = 50Hz, \pi = \frac{22}{7}, I = 15A, so that;

From equation 2,

X_{L}= \frac{240}{15}

    = 16Ω

To determine the inductance of the inductor,

X_{L} = 2\pifL

L = \frac{X_{L} }{2 \pi f}

  = \frac{16}{2*\frac{22}{7}*50 }

 = 0.05091

The inductance of the inductor is 0.051H.

4 0
4 years ago
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