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ryzh [129]
4 years ago
12

For a gearbox power and efficiency test apparatus that accommodates interchangeable gearboxes, drive up to 0.5kW. How to select

the motor for the test apparatus?
Engineering
1 answer:
BigorU [14]4 years ago
4 0

Answer:

First we must know the efficiency of the gearbox in which energy is lost by friction between its components, we divide this efficiency by the nominal power and find the real power.

With this value knowing the speed of rotation of the gearbox we select an engine that has a power just above.

Also keep in mind that the motor torque must be greater than the resistance offered by the gearbox and the 0.5Kw machine

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(Gas Mileage) Drivers are concerned with the mileage their automobiles get. One driver has kept track of several trips by record
Effectus [21]

Answer:

import java.util.*;

public class Main {

   

   public static void main(String[] args) {

     

       double milesPerGallon = 0;

       int totalMiles = 0;

       int totalGallons = 0;

       double totalMPG = 0;

       

       Scanner input = new Scanner(System.in);

 

       while(true){

           System.out.print("Enter the miles driven: ");

           int miles = input.nextInt();

           if(miles <= 0)

               break;

           else{

               System.out.print("Enter the gallons used: ");

               int gallons = input.nextInt();

               totalMiles += miles;

               totalGallons += gallons;

               milesPerGallon = (double) miles/gallons;

               totalMPG = (double) totalMiles / totalGallons;

               System.out.printf("Miles per gallon for this trip is: %.1f\n", milesPerGallon);

               System.out.printf("Total miles per gallon is: %.1f\n", totalMPG);

           }

       }

   }  

}

Explanation:

Initialize the variables

Create a while loop that iterates until the specified condition is met inside the loop

Inside the loop, ask the user to enter the miles. If the miles is less than or equal to 0, stop the loop. Otherwise, for each trip do the following: Ask the user to enter the gallons. Add the miles and gallons to totalMiles and totalGallons respectively. Calculate the milesPerGallon (divide miles by gallons). Calculate the totalMPG (divide totalMiles by totalGallons). Print the miles per gallon and total miles per gallon.

6 0
3 years ago
Write a function MaxMagnitude() with two integer input parameters that returns the largest magnitude value. Use the function in
Svetradugi [14.3K]

Answer:

The function requires evaluate the largest magnitude (the largest value withou sign), so we need to compare the absolute value of the two inputs number. For that we use the abs() function.

The code is as follows, with the comments after // and in italic font:

#include <iostream>   <em>//module for input/output stream objects</em>

#include <cmath>  <em>//math module </em>

using namespace std;

<em>// follows the function definition  </em>

int MaxMagnitude (int userVal1, int userVal2) {

 int Max=0;    <em>//define output variable Max</em>

 if (abs(userVal1) > abs(userVal2)) {  <em>// compare magnitude </em>

   Max = userVal1;  <em> //if Val1 is larger than val2 Max is Val1</em>

 }

 else {

   Max = userVal2;  <em>//else the max is Val 2 </em>

 }

 return Max;  <em>//the value returned for this function</em>

 }

// <em>in main we will use the defined function MaxMagnitude</em>

int main() {

  int one = 0;

 int two = 0;

 cin >> one;  //assignation of the first user input to one  

 cin >> two;   //assignation of the second user input to two  

//we call the function using as input the read values

//and write the return of the function, all at once  

  cout << MaxMagnitude(one, two) << endl;  

  return 0;

}

3 0
4 years ago
A rectangular weir is in a rectangular channel 2.9 m wide. The length of the weir is 1.9 m and is centered in the channel. If th
WINSTONCH [101]

Answer:

discharge = 0.310976 m³/s

Explanation:

given data

rectangular channel  wide = 2.9 m

length of weir L = 1.9 m

water level H = 0.2 m

solution

we get here discharge that is express as

discharge = \frac{2}{3} * C_d * L* \sqrt{2g} * H^{\frac{3}{2} }    ............................1

we consider here Coefficient of discharge Cd = 0.62

put here value we get

discharge = \frac{2}{3} * 0.62 * 1.9* \sqrt{2*9.8} * 0.2^{\frac{3}{2} }

discharge = 0.310976 m³/s

3 0
4 years ago
Water flows through a pipe and enters a section where the cross sectional area is larger. Viscosity, friction, and gravitational
BaLLatris [955]

Answer:

(A) and (D)

Explanation:

1) P2 is less than P1, that is when P1 increases in pressure, the velocity V1 of the water also increases. Therefore, on the other hand, since P2 is directly proportional to V1, P2 and V2 will be less than P1 and V1 respectively.

2) For P2 greater than P1 and V2 also is greater than V1. Since P2 is directly proportional to V2, hence, when P2 increases in pressure, P1 reduces in pressure. Similarly, velocity, V2 also increases and V1 reduces.

3 0
3 years ago
A vertical curve is designed for 55 mi h and has an intial grade of +2.5
Dafna1 [17]

Vertical curves are the curves which provide a vehicle to negotiate elevation rate change at a slow rate.

<u>Explanation:</u>

A vertical curve gives a progress between two slanted roadways, permitting a vehicle to arrange the height rate change at a slow rate as opposed to a sharp cut.

In any event four distinct criteria for building up lengths of list vertical bends are perceived somewhat. These are (1) front light sight separation, (2) rider comfort, (3) waste control, and (4) a dependable guideline for outward presentation.

8 0
4 years ago
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