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frutty [35]
2 years ago
5

Which graph(s) would represent this data?

Mathematics
1 answer:
LenaWriter [7]2 years ago
5 0

The types of graphs that can be used to represent the given data are; Bar Graph and Pie Charts

<h3 /><h3>How to use graphs?</h3>

We want to find out the type of graph that can be used to represent the data mass of Garbage collected each day of the week in a city.

Now, we can't use line graph because the data has no linear relationship between the two variables.

Secondly, the bar graph can be used as heights or lengths will be proportional to the mass of garbage collected each day.

Thirdly, a histogram cannot be used because this doesn't deal rang range of days but each single day.

Lastly, a pie chart can be used as we get the see the pie or in this case day with the highest mass of garbage on the pie chart.

Read more about Graphs at; brainly.com/question/4025726

#SPJ1

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4 Jillian's school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket salesfor
Kitty [74]
$10.50a + $3.75b = $2,071.50 It is given that b = 82 Therefore - $10.50a + ($3.75)(82) = $2,071.50 or $10.50a + $307.50 = $2,071.50 $10.50a = $2,071.50 - $307.50 = $1,764.00 Therefore - a (number of adult tickets sold) = $1,764.00/$10.50 = 168 tickets
4 0
3 years ago
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What is the standard form of (2+3i)(4-7i)/(1-I)
AlladinOne [14]
I believe in standard form this would be 31/2 + 27i/2
8 0
3 years ago
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What is the discriminant of 9x^2+=10x
prisoha [69]
9x^2-10x=0
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4 0
3 years ago
The prices of all college textbooks follow a bell-shaped distribution with a mean of $113 and a standard deviation of $12. Using
Soloha48 [4]

Step-by-step explanation:

In statistics, the empirical rule states that for a normally distributed random variable,

  • 68.27% of the data lies within one standard deviation of the mean.

  • 95.45% of the data lies within two standard deviations of the mean.

  • 99.73% of the data lies within three standard deviations of the mean.

In mathematical notation, as shown in the figure below (for a standard normal distribution), the empirical rule is described as

                             \Phi(\mu \ - \ \sigma \ \leq X \ \leq \mu \ + \ \sigma) \ = \ 0.6827 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi(\mu \ - \ 2\sigma \ \leq X \ \leq \mu \ + \ 2\sigma) \ = \ 0.9545 \qquad (4 \ \text{s.f.}) \\ \\ \\ \Phi}(\mu \ - \ 3\sigma \ \leq X \ \leq \mu \ + \ 3\sigma) \ = \ 0.9973 \qquad (4 \ \text{s.f.})

where the symbol \Phi (the uppercase greek alphabet phi) is the cumulative density function of the normal distribution, \mu is the mean and \sigma is the standard deviation of the normal distribution defined as N(\mu, \ \sigma).

According to the empirical rule stated above, the interval that contains the prices of 99.7% of college textbooks for a normal distribution N(113, \ 12),

                \Phi(113 \ - \ 3 \ \times \ 12 \ \leq \ X \ \leq \ 113 \ + \ 3 \ \times \ 12) \ = \ 0.9973 \\ \\ \\ \-\hspace{1.75cm} \Phi(113 \ - \ 36 \ \leq \ X \ \leq \ 113 \ + \ 36) \ = \ 0.9973 \\ \\ \\ \-\hspace{3.95cm} \Phi(77 \ \leq \ X \ \leq \ 149) \ = \ 0.9973

Therefore, the price of 99.7% of college textbooks falls inclusively between $77 and $149.

5 0
2 years ago
Can you guys help me on this?
Burka [1]

Answer:

1/3

Step-by-step explanation:

there's 9 socks in total and  3 black socks so if it's simplyfied it would be 1/3

5 0
3 years ago
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