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2 years ago

F(x) = -2x + 4 g(x) = 2x^2 – 2x - 8 Find: (gof)(x)

Mathematics

1 answer:

icang [17]2 years ago

5 0

Answer:

Step-by-step explanation:

$f(x)=-2x+4\\g(x)=2x^2-2x-8\\(g\circ f)(x)=g(f(x))\\=g(-2x+4)\\=2(-2x+4)^2-2(-2x+4)-8\\=2(4x^2-16x+16)+4x-8-8\\=8x^2+(-32x+4x)+(32-8-8)\\=8x^2-28x+16$

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antiseptic1488 [7]

what multiplied by what is 15 but added together is 8

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Answer: a

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3 years ago

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I need help please and can you explain <br> ANSWER ASAP!!!!

Andru [333]

The app uses 2^28 bytes.

Step-by-step explanation:

Step 1: Given total storage used by the app = 4^4 Megabytes. Also, 1 MB = 2^20 bytes. Find total storage used by app in bytes.

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3 years ago

If the area of a rectangle with length (4x) is 4x2 + 12x, find the width.

8090 [49]

Answer:

The width of a rectangle is: w = x+3

Step-by-step explanation:

Given

The length of rectangle = l = 4x

The area of rectangle = A = 4x² + 12x

To determine

The width of rectangle = w = ?

We know that the formula of the area of the rectangle is

$A = wl$

substitute A = 4x² + 12x and l = 4x in the equation to determine the width w of the rectangle

4x² + 12x = w×4x

w = [4x² + 12x] / [4x]

Factor 4x² + 12x: 4x(x+3)

w = [ 4x(x+3) ] / [4x]

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3 years ago

Cole is having his car repaired. The mechanic said it would cost at least $375 for parts

const2013 [10]

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Step-by-step explanation:

7 0

2 years ago

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What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

3 years ago